yes..only the application is different.
When they are in parallel the same voltage appear across both. The resistor carries a current of V/R, the inductor carries a current of V/(jwL). So the current in the inductor is 90 degrees behind in its phase.
I've been looking at them for a bit wondering the same question. I believe: When the switch is closed, the inductor will have a high resistance, limiting power directly from the main power source. During this time, the capacitor will be delivering voltage to the output. When the switch is open, the inductor will power the output while recharging the capacitor. From what i get it's not *necessary*, but does even out the voltage considerably. Maybe someone has a better answer...
Angle between v and i is 90 deg so, cos 90 = 0 Same for pure capacitor
an inductor has inductance(L). its unit is henry. when any change in currentin a inductor occurs it produces an self induced emf equal to e=-Ldi/dt volt. minus(-) sign indicates the direction of the induced voltage which is in opposition to the cause which is producing it. here the case is change in current(di/dt). that's why, whyan inductor opposes any change in voltage and hence current in it.
Yes.Source transformation in dependent voltage source can be solved the same like independent voltage source
The same as what? when an inductor is connected in series with a resistor and a current passed through them, the voltages across the resistor and inductor are equal when the reactance is equal to the resistance: 2.pi.f.L = R
When they are in parallel the same voltage appear across both. The resistor carries a current of V/R, the inductor carries a current of V/(jwL). So the current in the inductor is 90 degrees behind in its phase.
I've been looking at them for a bit wondering the same question. I believe: When the switch is closed, the inductor will have a high resistance, limiting power directly from the main power source. During this time, the capacitor will be delivering voltage to the output. When the switch is open, the inductor will power the output while recharging the capacitor. From what i get it's not *necessary*, but does even out the voltage considerably. Maybe someone has a better answer...
Since the equation of an inductor is ... di/dt = v/L ... then increasing the current in the RL network would cause a back-emf in the inductor that would initially seem to oppose the series current. More correctly, the question should ask "what if the voltage were increased?"; and the answer is that the rate of change of current in the inductor would increase, but the current would not initially change. This is the case for a series RL. For a parallel RL, increasing the current would initially show up as an increase the the current through the R, increasing voltage in the L, with the same effect as noted above.
The volt-amp characteristics will be same irrespective of current flow through that element. eg resistor, inductor.
Means you can go back and get money from the same source over and over again.
Voltage source inverters use the dc voltage (e.g a capacitor in parallel) as a source while the current source inverer (inductor in series) use the dc current as a source. Please note that voltage can not be changed abruptly in capacitor as current can not be changed abruptly in inductor.
Angle between v and i is 90 deg so, cos 90 = 0 Same for pure capacitor
The Fasel inductor is an electronic component inside the Wah Wah pedal that gives that real cool low end growl and wide sweeping depth to the Wah as heard in Hendrix's "Rainy Day, Dream Away". The Wah with the non-Fasel inductor sounds fine... until you hear a Wah with the Fasel inductor. Sadly the non-Fasel Wah pedal simply does not have the same growl and intensity as the Fasel Wah Wah pedal. I have both and tested them side by side. I'm trying to determine if my 1970s pedals have the Fasel or not.
No it wouldn't make sense, but if the book was written that way you could. There are some books written exactly that way. The back is the front and the front the back. Takes some getting use to.
There is no requirement to go to the same attorney. It can make sense to do so. The biggest concern is to make sure the new will cancels the old one.
an inductor has inductance(L). its unit is henry. when any change in currentin a inductor occurs it produces an self induced emf equal to e=-Ldi/dt volt. minus(-) sign indicates the direction of the induced voltage which is in opposition to the cause which is producing it. here the case is change in current(di/dt). that's why, whyan inductor opposes any change in voltage and hence current in it.