Resistance is inversely-proportional to the cross-sectional area of a conductor. For example, doubling its cross-sectional area will halve its resistance, while halving its cross-sectional area will double its resistance.
Since the cross-sectional area of a circular-section conductor is proportional to the square of its radius, doubling that radius will reduce its resistance by one quarter, while halving its radius will quadruple its resistance.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
Resistance depends on the thickness and length of the wire used, as well as the conductor used. For example, a short, thick wire made of copper will conduct electricity better than a long, thin wire made of, say, iron.AnswerResistance is directly proportional to the length and inversely proportional to the cross-sectional area (not 'thickness') of a material. Its constant of proportionality is called resistivity which is affected by temperature -so temperature indirectly affects resistance.
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voltage depend on current and resistance r.p.m depend on no of pole
Resistance is directly-proportional to the length and resistivity of a conductor, and inversely-proportional to its cross-sectional area. So a shorter wire would have less resistance than a longer wire made from the same material, and a wire with a greater cross-sectional area would have less resistance than one with a smaller cross-sectional area made from the same material. Resistivity depends on the material from which the wire is made, with some materials being better conductors than others. For example, silver has the lowest resistance compared with other metal conductors having identical dimensions. Similarly, a copper wire will have a lower resistance than an aluminium wire of identical dimensions.
If the radius of a wire is decreased by a factor of 3, the resistance of the wire will increase by a factor of 9. This is because resistance is inversely proportional to the cross-sectional area of the wire, which is proportional to the square of the radius. So, decreasing the radius by a factor of 3 will result in the area decreasing by a factor of 9, leading to a 9-fold increase in resistance.
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. This means that for a given material, a longer wire will have higher resistance and a thicker wire will have lower resistance. The relationship is described by the formula: Resistance = resistivity x (length / cross-sectional area).
No, the resistance of a wire primarily depends on its length, resistivity, and temperature. The cross-sectional area of the wire influences the wire's resistance indirectly by affecting the wire's overall resistance. A larger cross-sectional area generally results in lower resistance due to increased conducting area for current flow.
A piece of wire stretched such that its length increases and its radius decreases will tend to have its resistance increase. The formula for this is: R = ρL/A where ρ = resistivity of the material composing the wire, L = length of the wire, and A = area of the conducting cross section of the wire. It can easily be seen that as area decreases resistance gets higher. In the case proposed the wire length is not reduced as it is stretched to reduce the area, this increases the resistivity as well.
The resistance of a wire depends on three main factors: its length, its cross-sectional area, and the material it is made of. Generally, longer wires have higher resistance while thicker wires have lower resistance. The material's resistivity also plays a significant role in determining the wire's resistance.
The wire gets thinner when the resistance is less because there is less opposition to the flow of electrons, which results in less heat generation. This reduced heat generation allows for a thinner wire to be used without overheating.
If you double the radius of a wire then its cross-sectional area goes up by a factor of four. Put in the simplest way, this means that there's four times as much space for electrons to flow along the wire, hence one quarter the resistance.
The resistance of a connecting wire that is less than the resistance of a resistor would depend on the materials and dimensions of the wire and resistor. Generally, most connecting wires have very low resistance compared to resistors. Copper wires, for example, have low resistance and are commonly used for connecting circuits.
With a given material, the resistance is inversely proportional to its area of cross section and so the radius. That means wire becoming thinner the resistance increases not decreases as said in the question.
We know that, Circumference of the wire = 2πr Thus, resistance per unit volume of the wire = 4/2πr = 2/πr So, resistance of the specimen = 2/πr × 2r = 4/π And resistance of the halves of the wire = 2/πr × πr = 2 Now, Equivalent resistance will be decided as 4/(4+π) as 4/π,2,2 are in parallel combination.
The answer will depend on whether you require the radius, diameter or circumference.The answer will depend on whether you require the radius, diameter or circumference.The answer will depend on whether you require the radius, diameter or circumference.The answer will depend on whether you require the radius, diameter or circumference.
If the wire is short, its resistance will likely decrease. A shorter wire has less length for electrons to travel through, resulting in lower resistance according to the formula R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.