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If a 325 watt heater has a current of 6.0A what is the resistance?
Wiki User
∙ 13y ago
Watts = Current x Volts with your resistive heat application. To figure out resistance you need to know voltage and current. Since you are drawing 6 amps then Volts = 325/6. This means that there is about 54 volts supplying the heater which seems like a very strange supply voltage. Since Volts = Current x Resistance the resistance = 325/36.
Wiki User
∙ 13y ago
Anonymous
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What amp breaker do you need for a 325 watt heater 120 VAC?
Electrical breakers are sized by the conductor that is connected to it. The conductor is sized by the current that is drawn by the circuit. The formula for amperage is I = W/E. Amps + Watts/Volts. 325/120 = 2.7 amps. A #14 copper conductor is rated at 15 amps. This is the minimum size wiring that is used for house circuits loads. The breaker for this size wiring will be a 15 amp breaker.
What is the starting current for 110 kW motor?
If we consider the rpm to be 1450, then the full load current of 3 phase, 415V motor is approx 190 amps. Now, the starting current of a induction motor is 5-7 times the full load current. Hence the starting current will be approx 950 - 1330 amps. Similar calculations can be made for below mentioned ratings also: 110 KW, 220 V ------F.L. current: 350 amps 110KW, 240 V-------F.L. current: 325 amps
What value of resistor to light a LED on 230 volts?
To figure this out, you need to know the expected forward voltage and current of the LED. Lets assume 2ma and 2V. (Actually, 2ma is small, but I intend to make a point.) By Kirchoff's Voltage Law, you know that the signed sum of the voltage drops going around a series circuit must add up to zero. This means that the voltage across the resistor must be 228 volts. (-230 + 228 + 2 = 0) By Kirchoff's Current Law, you know that the signed sum of the currents entering a node is zero. As a consequence, you also know that the current at every point in a series circuit is the same. Therefore, the current through the resistor is also 2ma. By Ohm's Law, you know that resistance is voltage divided by current, so you know that the resistor is 228V divided by 2ma, which is 114K. The nearest standard value in the E12 scale is 100K. Recalculate the current for 100K, and you get about 2.25ma. (You could also use 120K, and I'll let you run the calculations yourself.) Don't stop here. There are some issues... By the power law, you know that power is voltage times current, so you know that the power dissipated by the resistor is 228V times 2.25ma, which is 513mW. I would put a one watt resistor in there. However, consider this. 2ma is a low current LED. Some of them pull 25ma. The power in the resistor in that case is about 6.5W, which is getting pretty high. Secondly, you need to consider the reverse breakdown voltage on the LED. I assume that when you said 230V, you meant AC, not DC, which means that there is going to be 230V (actually, a peak value of 325) across that LED for one half the line cycle. You need to check the datasheet and make sure the LED can handle that. If not, you need to put an ordinary signal diode, such as a 1N4148, in parallel with the LED, in the reverse direction, so that it clamps the reverse voltage at about 0.7 volts. (Don't worry about the reverse breakdown on the 1N4148, because the LED will protect it, on opposite half line cycles.) Last, but not least, you need to consider the safety of the operator. 230V is a high voltage, and LED's are not the most rugged thing around. If the LED breaks, you need to consider if its internal wiring could come into contact with the operator. I would certainly demand a UL listed device in this application.
Is there a standard and safe range for insulation resistance of motors or it's dependent on type of motorsif 30 Mohm is safe for a motor with 1000 Mohm of insulation resistance in normal conditions?
"INSULATION resistance is not about standard nd safe range because resistance value depend upon the application for which we are providing it in what range the current flows." The answer above is incorrect. Application and current rating & range have nothing to do with insulation resistance. There are standards available for insulation resistance testing both in terms of the test procedure and the values. IEEE Standard 43 provides a basis for insulation resistance testing. Both NETA ATS (Acceptance Testing Specification) and NFPA 70B gives criteria for insulation resistance testing. Insulation Resistance (IR) testing, also known by the slang terms meggering or megging, is a procedure where the quality of the electrical insulation is evaluated to determine if it is acceptable for service. It is also used to compare against previous measured values to determine if there has been any degradation to the equipment being tested. In this case we are talking about motor insulation. The question deals with two comparative readings and wants to know if the value of 30 megohms is acceptable. First we should clarify the test methods and results. NETA ATS 2007. Section 7.15.1 covers AC induction motors and generators. The testing involved is broken down into those motors 200 hp (150 kw) and less, and those > 200 hp (150 kw). The test voltage value is based upon the voltage rating of the motor's winding and is found in table 100.1: Rating = 250V; Test Voltage = 500 VDC; Minimum Resistance = 25 megohms Rating = 600V; Test Voltage = 1000 VDC; Minimum Resistance = 100 megohms Rating = 1000V; Test Voltage = 1000 VDC; Minimum Resistance = 100 megohms Rating = 2500V; Test Voltage = 1000 VDC; Minimum Resistance = 500 megohms Rating = 5000V; Test Voltage = 2500 VDC; Minimum Resistance = 1000 megohms Rating = 8000V; Test Voltage = 2500 VDC; Minimum Resistance = 2000 megohms Rating = 15000V; Test Voltage = 2500 VDC; Minimum Resistance = 5000 megohms Rating = 25000V; Test Voltage = 5000 VDC; Minimum Resistance = 20,000 megohms Rating = 34500V; Test Voltage = 15000 VDC; Minimum Resistance = 100,000 megohms It is important to note that the values given are based on a standard temperature of 40C (or sometimes 20C depending on the engineer's specification). You must correct your readings to a standard temperature as the value on the insulation's resistance is going to vary inversely with temperature. That is as temperature increases the resistance will decrease. The rule of thumb is that the measured value will halve for every 15C above standard and will double for every 15C below standard. As an example let us say that we have a 25 hp induction motor rated 480 VAC. The ambient temperature is 15C. Using our table we would set the tester to 1000 VDC and take a reading for one minute. At the end of the minute we get a reading of 450 megohms. Per NETA ATS Table 100.14 the correction factor is 0.31 so IR = 450 megohms x .031 = 139.5 megohms. The minimum acceptable value is 100 so this motor is acceptable. On the flip side if the motor is in a very warm process area, say 50C, then temperature correction factor is 1.59 thus IR = 450 megohms x 1.59 = 716 megohms. As you can see the temperature makes a very large difference in the results! This discussion up to this point has been about a spot-reading check. However for a true check we want to know the Dielectric Absorption value. There are two different standard tests for Dielectric Absorption. The first is the Dielectric Absorption Ratio (DAR) and the second is the Polarization Index. DAR = Reading @ 60 sec / Reading @ 30 sec. Let us say that the 30 sec reading = 325 megohms and the 60 sec = 450 megohms. Thus: DAR = 450 megohms / 325 megohms = 1.38 The minimum DAR per NETA is 1.4 so this particular motor is borderline at best and should be investigated further. PI = Reading @ 10 min / Reading @ 1 min. Let us say that the 1 min reading = 450 megohms and the 10 min = 1100 megohms. Thus: PI = 1100 megohms / 450 megohms = 2.44 The minimum PI per NETA is 2.0 so in this case the motors is acceptable. One final factor that should be taken into consideration is Relative Humidity (RH). The amount of moisture present in the air also affects the measured test values. The more moisture then the lower the reading. There is no published standard correction factor for RH however when NETA Techs perform these tests then they always record the RH for baseline comparison. The bottom line is that the readings will vary based upon temperature and humidity. A reading on warm humid day may be acceptable whereas the same reading on a cold dry day may not. So the question asked here is unanswerable as there is not enough information given. What were the temperatures at the time of the readings? Was it dry during one and raining during the other? What does the person asking mean by "normal conditions"? I highly recommend that anyone interested in this subject get the free book "A Stitch in Time" by Biddle at: http://www.biddlemegger.com/biddle/Stitch-new.pdf Please note that I also changed the category from Health/pregnancy to Electrical Engineering.
What size wire is required for 325 amp service?
A 350 MCM copper conductor with an insulation rating of 90 degree C is rated at 350 amps.
What amp breaker do you need for a 325 watt heater 120 VAC?
Electrical breakers are sized by the conductor that is connected to it. The conductor is sized by the current that is drawn by the circuit. The formula for amperage is I = W/E. Amps + Watts/Volts. 325/120 = 2.7 amps. A #14 copper conductor is rated at 15 amps. This is the minimum size wiring that is used for house circuits loads. The breaker for this size wiring will be a 15 amp breaker.
How to replace BMW 325 heater core?
how hard is it to replace a heater core on a 87 325e BMW 2 dr? thank you in advance.
How would you get a manual for a teledyne laars series one propane 325 heater its not on the jandy website?
Write or inquire thru that web site for a manual to be sent to you. k
What is 15 percent of 325?
15% of 325= 15% * 325= 0.15 * 325= 48.75
What is 57 percent of 325?
57% of 325= 57% * 325= 0.57 * 325= 185.25
What is 24 percent of 325?
24% of 325= 24% * 325= 0.24 * 325= 78
What is 75 percent of 325?
75% of 325 = 75% * 325 = 0.75 * 325 = 243.75
What is 75 percent of 325 dollars?
75% of $325= 75% * 325= 0.75 * 325= $243.75
What is 325 percent of 100?
325 percent of 100 is 325.
What is the fraction for 325?
As a fraction, 325 = 325/1
What are the features of the KitchenAid Artisan Stand Mixer?
The KitchenAid Artisan Stand mixer has many features. Some of these features are 10-speed solid state control, a pouring shield, and 325 watt heavy duty motor.
Can a 1994 browning 325 shoot steel?
You will need to contact Browning for a current and correct answer. Try their web site first unde FAQ
