Well, isn't that a happy little question! To find the starting current for a 110 kW motor, you can use the formula: Starting Current = (Motor Power / (sqrt(3) x Voltage x Power Factor x Efficiency)). Remember, it's all about happy little calculations and making sure your motor has a smooth and joyful start.
starting current of 3 phase 75 KW induction motor
Assuming the Motor is IE1 Efficiency and 4 Poles, the in rush current will be 1183 A
The starting current is high because the motor's rotor winding has very low resistance. It's similar to a transformer with a shorted secondary windings. As the motor accelerates,the back emf increases which resist the flow of current in the rotor winding. Hence,the current drop to the rated full-load value.
Maximum current is defined by the rated KW of the device, say Motor. The motor may not run at its maximum rated capacity all the time. Nominal current is drawn when motor runs at nominal load.
FLA: Full Load Ampere. Its the current drawn by the motor when the motor is running at full load FLA = kW / (1.732*V*pf*efficiency*100)
starting current of 3 phase 75 KW induction motor
Assuming the Motor is IE1 Efficiency and 4 Poles, the in rush current will be 1183 A
depending on kva class of the motor between 4-8 times the running current
110 volts divided by 1,300 watts(1.3 kw) = .09 kw or 900 watts.
The cable size depends on a few factors, such as the supply voltage, the method of starting the motor, (direct-on-line, or star delta) and the length of cable required to compensate for voltage drop. Also, if the cable is copper or aluminum.110 kW motor has a rated current of 200 amps at 415 volts, so the correct copper cable size would have a cross-sectional area of 75 square mm., if the motor is started direct-on-line.At 660 volts, the rated current would be 118 volts and the cable size would be 35 square mm.
As the motor is drawing 9.7×110 = 1,067 watts (or 1.067 kW), and delivering 1.25×746 watts (or .9325 kW) of mechanical energy, it should release 1,067-932.5 = 134.5 watts (or .1345 kW) of heat.
The current depends on the supply voltage.
The starting current is high because the motor's rotor winding has very low resistance. It's similar to a transformer with a shorted secondary windings. As the motor accelerates,the back emf increases which resist the flow of current in the rotor winding. Hence,the current drop to the rated full-load value.
3phese 460 volt 75 kw a/c drivi full load current
you need the current of motor or the KW/HP rating
It depends on what you mean by 'converter'; I'm not aware of such a machine. <<>> No, a 4 kW rotophase will not handle the start up current of a 4 kW 3 phase motor.
starting current of 315 kw motor in start delta 2.5 time for single sec. if your cable lingth 130 meter u can use 150mm2 (3 cable per phase) 150mm2 single cable current 292 Amp voltage drop 0.28/meters so u can use breaker 1000 Amp and set Im time (for starting current) setting avalible in breaker.