A: All transistor experience some kind of leakage with the one of the three termianal open. it called Iceo.
Consider that current flow "enters" at the emitter and "exits" at the collector and base. Now, IE = IB + IC. Alternately, current "enters" at the collector and the base, and "exits" at the emitter. Now, IE = IB + IC
Common base transistor if the emitter is open current Ie=0 but a small collector current thus exist.this current is reversed biased collector to the base voltage it is represented by Icbo while common emitter is d base terminal is open circuit and the base junction is reversed biased current Icbo flow from the tcollector to the emitter in the external circuit this current is called leakage current.
In the common emitter configuration, a class A amplifier, an increase in base voltage (the input) leads to an increase in base-emitter current which leads to a proportionately larger increase in base collector current. That pulls the collector towards the emitter, which decreases the collector voltage. Since the collector is the output, this configuration is an inverting amplifier.
The active region of a transistor is when the transistor has sufficient base current to turn the transistor on and for a larger current to flow from emitter to collector. This is the region where the transistor is on and fully operating.
Collector has larger area than base and emitter because base collector is reverse biased, hence the current flow here due to the minority carriers and the large power dissipation takes place by the majority carriers, this power dissipated in the form of heat.. To cool the device from heat we made the larger area........
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
Consider that current flow "enters" at the emitter and "exits" at the collector and base. Now, IE = IB + IC. Alternately, current "enters" at the collector and the base, and "exits" at the emitter. Now, IE = IB + IC
A; The base must be positive with respect to the emitter this condition will allow collector current to flow from collector to emitter. If the transistor manage to get saturated the current can flow in both direction. as a switch
No. For BJTs, they have a natural amplification, B, of current between the base current to collector current. In rough calculations, I've often used 50. So applying 20uA of current to the base of a BJT should cause 1mA of current to flow through the collector (assuming base, collector, and emitter resistors are sized appropriately so this is not limitted). The emitter will see the base current + the collector current.
Three legs on a transistor are represented by these letters E Emitter =you connect your input depending on type of your transisitor neg or pos B Base = you connect control input again depends on type C collector = here comes your amplified output there are 2 types of transistors PNP and NPN there is no current flow from emitter to collector when ther is no control input at the base. a very small opposite current to the emitter polarity make current flow multiplied by the amplification factor of each transistor. if you use a sound frequency input at the base you have amplified sound output at collector if you just use dc you have amplified dc current output. some transistors leak current to kill that unwanted flow through collector use a small resister from emitter to base.
Common base transistor if the emitter is open current Ie=0 but a small collector current thus exist.this current is reversed biased collector to the base voltage it is represented by Icbo while common emitter is d base terminal is open circuit and the base junction is reversed biased current Icbo flow from the tcollector to the emitter in the external circuit this current is called leakage current.
A: As base current increases the collector current increases to a point where any more base current will not increases the collector current at hat point the transistor is saturated whereby current may flow in both direction and the two diodes will essentially be in a parallel mode and the voltage drop from emitter to collector will reflect the status as a low voltage drop.
For proper working of a transistor,the voltage at the base region must be more positive than that of the emitter region.The voltage at the collector region, in turn, must be more positive than that of the base region.when voltage is applied to transistor, the emitter supplies electron,which is pulled by the base from the emitter as it is more positive than the emitter.This movement of electrons from emitter to collector creates as flow of electricity through the transistor.The current passes from the emitter to the collector through the base.Thus, adjustment of voltage in the base region modifies the flow of the current in the transistor by changing the number of electron in the base region. In this way, small changes in the base voltage can cause large changes in the current flowing out of the collector. We have three transistor element, a.)Emitter b.)Base c.)Collector
In the common emitter configuration, a class A amplifier, an increase in base voltage (the input) leads to an increase in base-emitter current which leads to a proportionately larger increase in base collector current. That pulls the collector towards the emitter, which decreases the collector voltage. Since the collector is the output, this configuration is an inverting amplifier.
A transistor controls the flow of current between the emitter and collector. The larger current is supplied by the power supply, across the emitter and collector. The flow is then controlled by a small current applied to the base connection. So, a large current flow mimics the small signal current. Limits are reached, when the transistor gets close to being fully switched on or off. This will cause distortion. To avoid this, more amplification is provided by a series of transistor amplifiers, one after the other.