Bandwidth is the output of some light source, the width of the frequency range which can be transmitted by some element, the gain bandwidth of an optical amplifierthe width of the range of some other phenomenon. It's values may be specified in terms of frequency or wavelength.
wavenumber= 1/wavelength
the channel capacity (information in bits per second) is related to bandwidth and SNR by the relation C= B[log(1+SNR) b/s log is at the base 2 B= bandwidth of a channel C= capacity in bits per second SNR= signal to noise ratio.
C=blog(1+s/n)
It's the property of the material which allow only certain bandwidth of wavelength. Materials that exhibit this property is known as photonic crystal. In order to exhibit this property the material has to have a periodic arrangement of dielectric structures with periodicity of the order of wavelength.
The roll-off factor of a digital filter defines how much more bandwidth the filter occupies than that of an ideal "brick-wall" filter, whose bandwidth is the theoretical minimum Nyquist bandwidth. The Nyquist bandwidth is simply the symbol rate expressed in Hz: Nyquist Bandwidth (Hz) = Symbol Rate (Sym/s) However, a real-world filter will require more bandwidth, and the excess over the Nyquist bandwidth is expressed by the roll-off factor. Suppose a filter has a Nyquist bandwidth of 100 MHz but actually occupies 120 MHz; in this case its roll-off factor is 0.2, i.e. the excess bandwidth is 0.2 times the Nyquist bandwidth and the total filter pass-bandwidth is 1.2 times the Nyquist bandwidth.
There is a relation between transmission media and bandwidth. The transmission media cannot exceed the amount of bandwidth available. The transmission of media is limited to the bandwidth.
There is really no relation.
Bn>B3bn
Use the relation: speed = frequency x wavelengthUse the relation: speed = frequency x wavelengthUse the relation: speed = frequency x wavelengthUse the relation: speed = frequency x wavelength
Wavelength x amplitude = speed of the wave.
wavenumber= 1/wavelength
The product of bandwidth and gain is constant. If bandwidth increases then gain decreases and vice versa.
when numerical aperture increases ,there will be greater lss and low bandwidth...jahi
Speed = (frequency) times (wavelength) Frequency = (speed) divided by (wavelength) Wavelength = (speed) divided by (frequency)
delta_f = c * delta_lambda / (lambda*lambda) where delta_f is the bandwidth range, c is the light speed, delta_lamba is the wavelength range, and lambda is a certain wavelength. Therefore, delta_f = 3*10e8 * 0.1*10e-6 / (10e-6 * 10e-6) = 3*10e13Hz = 30THz
dispersion increases and wavelength decreases
the channel capacity (information in bits per second) is related to bandwidth and SNR by the relation C= B[log(1+SNR) b/s log is at the base 2 B= bandwidth of a channel C= capacity in bits per second SNR= signal to noise ratio.