A: A transformer will transform the AC input to a low or hi output as required by a ratio of input to output. The power will be expressed a KVA or kilo volts to ampere ratio. It also will have a rating of maximum voltage for the simple reason of winding to winding insulation and primary to secondary isolation because if breakdown occurs the transformer will burn out promptly.
The ratings state the limits on voltage and current for operating the transformer at full load. The rated voltage times the rated current gives the rated VA of the transformer. Transormers are not usually rated directly for power because this depends on the power factor of the load applied.
Assuming that the voltage rating of the lamp matches the rated secondary voltage of the transformer, the lamp will operate at its rated power.
Apparent power is the product of voltage and current in an a.c. system, and is expressed in volt amperes. The rated apparent power of a transformer is the product of its rated secondary current and rated secondary voltage.
This is the rated output of the transformer, obtained by multiplying the rated secondary voltage by the rated secondary current. And it's 'kV.A', not 'kva'.
Presumably you are asking about the rated secondary current of a transformer rated at 2200 kV.A?This depends on the rated secondary voltage. You divide the rated apparent power of the transformer by the rated secondary voltage.Of course, the actual current depends on the load.
The ratings state the limits on voltage and current for operating the transformer at full load. The rated voltage times the rated current gives the rated VA of the transformer. Transormers are not usually rated directly for power because this depends on the power factor of the load applied.
Because it's the product of the transformer's rated secondary voltage and its rated secondary current. The product of voltage and current, in a.c., is the volt ampere.Incidentally, it's 'kV.A', not 'kva'.
The product of the secondary rated current and the secondary rated voltage will give you the rated V.A of the transformer.
Assuming that the voltage rating of the lamp matches the rated secondary voltage of the transformer, the lamp will operate at its rated power.
Apparent power is the product of voltage and current in an a.c. system, and is expressed in volt amperes. The rated apparent power of a transformer is the product of its rated secondary current and rated secondary voltage.
Presumably, you are asking what is the rated secondary current for a 45 kV.A (not 'kva') transformer? The answer depends on its rated secondary voltage. To obtain the rated secondary current, you divide the (apparent) power rating by its secondary rated voltage.
the voltage which is mainly applied to primary side of the transformer is called rated voltage.Answer'Rated voltage' is the nominal voltage at which an electrical device has been designed to operate.
This is the rated output of the transformer, obtained by multiplying the rated secondary voltage by the rated secondary current. And it's 'kV.A', not 'kva'.
The correct symbol for kilovolt amperes is 'kV.A, not kva. A volt ampere is the product of the transformer's secondary rated voltage and its rated current. It is not rated in watts, because the transformer designer has no idea what sort of load is to be applied to the transformer, and it is the load that determines the amount of watts, not the transformer.
The output voltage of a transformer is not connected to the maximum rated current. You state that the transformer is rated at 12-0-12 at a current of 1A, therefore the maximum (rated) current on the secondary would be 1A. Normally, transformers are rated in VA (volt amps) which is simply voltage x current, the voltage across the two 12v terminals would be 12+12 volts, making the rating of the transformer 24VA.
kva k-kilo v-voltage a-amps(current)
Presumably you are asking about the rated secondary current of a transformer rated at 2200 kV.A?This depends on the rated secondary voltage. You divide the rated apparent power of the transformer by the rated secondary voltage.Of course, the actual current depends on the load.