1. Theoretical Answer
R=1.5/25=0.6 Ohms
2. Practical Answer: Dry cells will not be able to deliver 25A as there are two limtation
a) Internal Resistance that limits the max current.round couple of Ohms. Max current that it can supply is about 1-2 A.
b) Capacity of Dry cells which are typical 700maHr. Even if cell could supply 25A it will only be for 1.7 minutes and then cell will become dead.
c) as the cells get drained there is increase in internal resistance which will further reduce the current.
By Ohm's Law Voltage = Current x Resistance R = V / I = 120 / 12 = 10 Ohms
- For a single phase supply @ 220 voltscurrent drawn by 5kva UPS = 22.7 amperes (at full load.)
because at start the motor draws larger quantity of current and this may affected the rotor windings in order to limit current always resistance is connected.
A: If the transformer is connected to a power input of course it will draw current. The primary is a long wire it has own resistance wrap around an iron core. Of course there will be primary current whether there is a load on the secondary or not.
Is this, intentionally, a trick question?We are dealing with alternating current, here, not direct current. So, if you divide the supply voltage by the current drawn by the television set, you are determining its impedance(Z), not its resistance:Z = V/I = 120/3 = 40 ohmsImpedance is the vector sum of resistance and reactance. As the current is probably being drawn by a transformer, the resistance will be significantly lower than the reactance, perhaps only an ohm or two -if that!So, from the information supplied, you cannot determine the resistance.
I have no idea
v/i=r so 120/0.25=480 480 ohms is the resistance
The formula is Resistance= Voltage/ Amps(current) In your example: R=50/2.5, so the answer is 20 ohms.
4 resistors were connected in parallel it yields 5A of current from 220V supply.
A light doesn't output current, it "draws" current based on voltage and its resistance. Voltage = Current x Resistance or Current = Voltage / Resistance. (Ohm's Law)
The voltage of a battery goes as the current times the resistance (V=IR). Because the voltage is being held constant, the resistor that draws the most current will have the lower resistance.
By Ohm's Law Voltage = Current x Resistance R = V / I = 120 / 12 = 10 Ohms
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.If a 100-watt bulb draws 0.87 amperes of current, 17 of them will draw about 14.8 amperes, (0.87 times 17), if they were wired in parallel.However, wiring them in series would not give you 0.051 amperes, (0.87 divided by 17), as one might expect, because the resistance-temperature coefficient of bulbs is quite dramatic, so more current would actually be drawn because the bulbs would be much cooler. How much more would require testing. You could do this by supplying 6.8 volts to one bulb and seeing what you get, or just hook 17 of them up in series to 115V.
Given R=? I=12 ampere V=120 Volts equation I=V divided R Solution; R=12 ampere 120 Volts answer (10)
Suppose we have a circuit containing a 15 volt battery and two 10 ohm resistors, and those resistors are in parallel. The total resistance of the two 10 ohm resistors = 5 ohms (1/10 + 1/10 = 1/5). Therefore the total amount of current flowing from the battery = 15/5 = 3 amperes. Adding a third 10 ohm resistor in parallel to the other two means that the total resistance of the circuit is now 3.333 ohms (1/10 + 1/10 + 1/10 = 1/3.333. Therefore the total current flowing from the battery = 15/3.33 = 4.5 amperes. Parallel resistances can be thought of as separate circuits. If we had a circuit containing a 15 V battery and a 10 ohm resistor, then 1.5 amperes would flow around that circuit (V = IR, 15 =10 x 1.5). If you keep adding 10 ohm resistors in parallel then the total current flowing out of the battery will step up accordingly: 1 resistor draws 1.5 amps, 2 draws 3 amps, 3 draws 4.5 amps, 4 draws 6 amps etc.
The power used, assuming Unity Power Factor (resistive load), is the product of resistance and the square of the current -- or 1210 Watts.
12 Amperes is.