It depends on the resistance of the galvanometer and the current required to reach full scale. A 100 ohm meter requiring 1 milliampere would require 99.9 KOhms in series to become a 100 volt voltmeter.
Since Galvanometer is a very sensitive instrument therefore it can't measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low resistance known as "shunt" resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt. In this way a Galvanometer is converted into Ammeter and can measure heavy currents without fully deflected.
we can measure the resistance of the motor by using voltmeter ammeter method of by directly using a multimeter across the armature terminals of the motor in voltmeter ammeter method we should use a less value of dc voltage to find the resistance
Smoke. Since a voltmeter is in parallel with the load it is right across the source voltage. Putting the amp meter across the line with its low resistance it will act like a fuse, hence the smoke. Newer solid state testers are usually smarter that the operators. They have built in circuitry which sense the wrong settings you are using and shut the tester off with a "beep" to let you know that you are doing something wrong.
The equation you are looking for is R = E/I. The question wants to see if you know how to convert mA to amps. Do the conversion and then use the equation and you will have your answer.
I am going to assume that you mean low "resistance" in an open circuit test and are performing this with a multimeter. An ammeter works by place a very small amount of resistance in series with a circuit and then measuring the Voltage drop across the resistance. The Voltage is directly proportional to the current as given in ohms law: E = I x R If you are measuring the resistance through the ammeter it will have a very low resistance and impedance.
That won't work. To convert an ammeter (a galvanometer is a very sensitive type of ammeter) you connect a high value resistor in series with it.
"An ohmmeter is an electrical instrument that measures electrical resistance, the opposition to an electric current."The unit of measurement for resistance is ohms (Ω).It is useful device for rapid measurement of resistance. It is consist of galvanometer and adjustable resistance Rs of known value and a cell connected in series. The resistance R to be measured is connected between the terminals.The series resistance Rs is so adjusted that when the terminals are short circuited i.e., when R = 0, the galvanometer gives full scale deflection. So the extreme graduation of the usual scale the galvanometer is marked 0 for resistance measurement. When terminals are not joined no current passes through the galvanometer and its deflection will be zero . Thus zero of the scale marked as infinity. . When R is not infinite , the galvanometer deflects to some intermediate point depending on the value of R scale can be calibrated to read the resistance directly.
It depends on the resistance of the galvanometer and its full scale current. A 100 ohm meter reading 1 milliampere would require 0.1 volts to reach full scale, so it would require about 0.1 ohms in parallel to become a 1 ampere ammeter.
Since Galvanometer is a very sensitive instrument therefore it can't measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low resistance known as "shunt" resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt. In this way a Galvanometer is converted into Ammeter and can measure heavy currents without fully deflected.
if we would like to expand the range of voltmeter we should change the voltmeter resistance even to be appropriate . we should use a variable resistance to control of its value . I would extend the range of a voltmeter by adding resistance in series with it. I would extend the range of an ammeter by connecting resistance in paerallel with it.
we can measure the resistance of the motor by using voltmeter ammeter method of by directly using a multimeter across the armature terminals of the motor in voltmeter ammeter method we should use a less value of dc voltage to find the resistance
The ammeter is basically a Galvanometer with a small resistance to parallel with it. As we know that, if we connect two resistances in parallel, then the equivalent resistance is equal to the the value which is less than the value of lowest resistance connected in parallel. suppose if we connect 1 ohm & 0.1 ohm in parallel, then the equivalent of it will be 0.0909 ohm (less than 0.1 ohm). means in parallel circuit the equivalent resistance become smaller. as like this a small parallel resistance across galvanometer decreases the value of the value of resistance of it. since it gets very small value, so it connected in series to measure the value of current in the circuit. due to very low resistance, it drops very low voltage on it ( upto can be negligible) so we assume that it works like a short circuit.
Actually ammeter is a galvanometer which is shunted by a resistance called shunt. For large currents major part of it is bypassed through the shunt. The parallel combination of shunt resistance and meter resistance is added to the circuit resistances , so the value indicated by the ammeter is slightly lesser than the actually value.
http://books.google.co.in/books?id=Y-ruqUWv5UIC&pg=PA157&lpg=PA157&dq=ballistic+galvanometer+leakage+method&source=bl&ots=ZNigwuasnM&sig=KPDIj8E3asAS2xuNjSurDIB3fAA&hl=en&sa=X&ei=6oc8UZ_qIMfPrQf6ooCIDQ&ved=0CD0Q6AEwAw#v=onepage&q=ballistic%20galvanometer%20leakage%20method&f=false
A: the resistance should be decreased to 1/2 its value for half scale reading or use any ratio [ decrease] to obtain a correct reading.
Any standard voltmeter but however the voltage to be measured must be stepped down to a safe value using a Potential transformer.
futf