Ohm's law:
5a
The voltage is 3 x 36 or 108 volts.
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.
Looking for coil ohms and stator ohms. And possibly the voltage comming out of the stator .
V=I*R -- Potential (Voltage, V) = Current (Amperage, I) * Resistance (Ohms)2A*5Ohms = 10V
The voltage is 3 x 36 or 108 volts.
The voltage of a circuit with a resistance of 250 ohms and a current of 0.95 amps is 237.5 volts. Ohms's law: Voltage = Current times Resistance
Ohm's Law: voltage is current times resistance, so 8 amps times 2 ohms is 16 volts.
9V by using ohms law
Just use Ohm's Law: V=IR (voltage = current x resistance; using units: volts = amperes x ohms).
12 volts
No, a miliohm is 0.001 ohms. A kiloohm is 1000 ohms.
Voltage is not measured in ohms. It is measured in volts.
Ohm's Law requires you know two of three parameters to calculate the third. Volts = Amps x Ohms You need to know current flowing through resistance to calculate voltage drop.
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
If the resistance of the wire is 30 ohms and the voltage between the two ends of the wire is 45 volts,then the current through the wire isI = E/R = (45/30) = 1.5 amperes.
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.