The value for resistivity will remain unchanged (provided temperature remains constant). Resistivity is a property of the material. The resistance, however, will double. Remember that resistance is directly proportianal to the length of the conductor and inversely proportional to the cross-sectional area of the conductor.
Work it out for yourself. The equation is: R = resistivity x (length/area). Incidentally, 1.55 m2 is an enormous area, if you are describing a conductor!!!! And 2.8 doesn't appear to represent a practical value of resistivity.
In order to calculate the resistance of a material (typically a wire), you need three parameters: length of the conductor, cross-sectional area of the conductor, and resistivity of the material. These are then used in the following equation:R = ρ·L/A (Resistance = resistivity [Ω·m] x length [m] / area [m2])Assuming you are using copper cabling, then the resistivity you must use for copper is approximately 16.78 nΩ·m, or 1.678 x 10-8 Ω·m.Substituting the other two values yields a resistance value of R = 1.119 Ω. This is only the resistance of a single conductor, however, so depending on your application you may need to consider the resistance of the other two conductors as well.
If the resistance is increased the current, which is inversely proportional, decreases and, the voltage drop increases.
Resistance will decreases... Because R is inversely proportional to Area of the conductor.AnswerIf the conductor has a circular cross-sectional area, then doubling the diameter will reduce the resistance to one quarter of its original distance. This is because area is proportional to the square of the radius, and resistance is inversely proportional to cross-sectional area.
The correct term is 'current', not 'amperage'. The answer is that nothing will happen to the resistance. Having said that, changing the resistance will cause current to change for a fixed value of voltage.Resistance is determined by the length, cross-sectional area, and resistivity of a material. Resistivity is affected by temperature, so resistance is also therefore indirectly affected by temperature. Only by changing one of these variables will the resistance change.Since the ratio of voltage to current will tell us what the resistance of a circuit happens to be (it's not affected by that ratio) for a particular ratio, the ratio will increase (as per your question) if the resistance increases. But it's not the ratio that's affecting resistance, its the resistance affecting the ratio!
Resistance is the value of a given wire in ohm but resistivity is value of the material with which that wire is made in ohm meter. R = rho * L / A Here rho is resistivity and R is resistance. L is the length of the wire and A is area of cross section
The value of resistivity of human skin is 0.2 Ohm-meters
Work it out for yourself. The equation you will need to use is: resistance = resistivity x (cross-sectional area / length) Manipulate the equation to make 'length' the subject, and use 17.25 x 10-9 ohm metres as the value of resistivity.
Electrical resistance is measure in Ohms. A function of voltage divided by current. It is also dependant on the length and cross sectional area of the conductor.
Work it out for yourself. The equation is: R = resistivity x (length/area). Incidentally, 1.55 m2 is an enormous area, if you are describing a conductor!!!! And 2.8 doesn't appear to represent a practical value of resistivity.
When we increment the pointer its value is increased by the length of the data type that it points to.
You multiply the length times the with.
It can be because of the material used.As we know R=PL/A where R=resistance P=resistivity of the material used L=length of the conductor A=area of cross section of the conductor
Over 25 times A+ answers
the P.H. value of fresh water is 7 & the P.H. value of saline water is less than 7.
Assume that the increase in length is achieved by uniform reduction in the cross-sectional area of the wire. Then an increase in length by 4 times will result in the cross sectional area being reduced to a fifth of it original value. This will increase the resistance to five times its previous value.
In order to calculate the resistance of a material (typically a wire), you need three parameters: length of the conductor, cross-sectional area of the conductor, and resistivity of the material. These are then used in the following equation:R = ρ·L/A (Resistance = resistivity [Ω·m] x length [m] / area [m2])Assuming you are using copper cabling, then the resistivity you must use for copper is approximately 16.78 nΩ·m, or 1.678 x 10-8 Ω·m.Substituting the other two values yields a resistance value of R = 1.119 Ω. This is only the resistance of a single conductor, however, so depending on your application you may need to consider the resistance of the other two conductors as well.