Because reactance of capacitor is inversly proportional to the frequency i.e-
Xc=1/(2*pie*f*c)
where f is frequency
and c is capacitance of capacitor.
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
The capacitive reactance of a capacitor increases as the frequency decreases.
The capacitive reactance of a 1 µF capacitor at a frequency of 60 Hz is about 2700 ohms.
Since capacitive reactance is inversely-proportional to the supply frequency, as the frequency is increased, the reactance will decrease.
943H
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
Reactance (in ohms) = 1/(2 pi * capacitance * frequency). Capacitance is in farads. Frequency is in Hertz (cycles/second). So increasing capacitance or increasing frequency will decrease reactance.
The capacitive reactance of a capacitor increases as the frequency decreases.
The reactance of a capacitor is a function of -- the capacitance of the capacitor -- the frequency of the voltage across the capacitor
capacitive reactance is inversely proportional to the capacitance of the capacitor and frequency of the AC line reactance (in ohms) = 1/(capacitance * frequency)
The capacitive reactance of a 1 µF capacitor at a frequency of 60 Hz is about 2700 ohms.
A capacitor will oppose the flow of a.c. due to its capacitive reactance (Xc), expressed in ohms.The capacitive reactance for a given capacitor is inversely-proportional to the frequency of the supply; in other words, the higher the frequency, to lower the capacitive reactance.
Capacitive reactance (expressed in ohms) is inversely-proportional to the supply frequency, so it will decrease when the frequency increases. The following equation applies:XC = 1/(2 pi f C)where:XC = capacitive reactance, in ohmsf = frequency, in hertzC = capacitance, in farads
yes, capacitive reactance is inversely proportional to frequency.
It is the capacitive reactance of a capacitor that causes it to oppose the passage of a.c. current. Since capacitive reactance is inversely-proportional to frequency, the lower the frequency, the greater its reactance, and the more it will oppose the flow of a.c.
Since capacitive reactance is inversely-proportional to the supply frequency, as the frequency is increased, the reactance will decrease.
Capacitors have an equivalent reactance of 1/jwC (ohms) where w is the angular frequency of the AC signal and C is the capacitance. As the frequency of the signal across the capacitor increases, the capacitor reactance approaches 0 (capacitor acts like a short circuit). As the frequency of the signal across the capacitor decreases, the capacitor reactance approaches infinity (capacitor acts like an open circuit). So, if you have a high frequency signal (like a step input) the capacitor will momentarily act like a short.