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The total current flowing in the three resistors,

i = 110 V / r(eq); where r(eq) is the equivalent resistance of the three parallel resistors.

r(eq) = 1/[(1/20) + (1/60) + (1/80)] = 1 / 0.079 ohms = 12.63 ohms.

i = 110 V / 12.63 ohms = 8.71 amps.

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