The final current is E/R = 0.262 = 3/R.
R = 3/0.262 ( = 11.45 ohms ).
The time constant is RL = 0.532.
L = 0.532 / R = (0.532) / (3/0.262) = (0.532) (0.262) / 3
= 46.46 millihenrys (rounded)
The same as what? when an inductor is connected in series with a resistor and a current passed through them, the voltages across the resistor and inductor are equal when the reactance is equal to the resistance: 2.pi.f.L = R
t = L/R
A circuit in which elements are connected in series.For example in RLC series circuit resistor,inductor and capacitor are connected in series.
The same as the time constant of a 2.7 microfarad capacitor and a 33 ohm resistor connected in series.
Simple...(20*10-3)/230=869 microseconds
The same as what? when an inductor is connected in series with a resistor and a current passed through them, the voltages across the resistor and inductor are equal when the reactance is equal to the resistance: 2.pi.f.L = R
The time constant (τ) of a circuit consisting of an inductor (L) and a resistor (R) in series is given by the formula τ = L/R. In this case, with L = 50mH and R = 200 ohms, the time constant would be τ = (50mH) / (200 ohms) = 0.25 milliseconds.
RL circuit consists of a resistor and an inductor connected in series, while an RC circuit consists of a resistor and a capacitor connected in series. In an RL circuit, the time constant is determined by the resistance and inductance, while in an RC circuit, the time constant is determined by the resistance and capacitance. RL circuits respond to changes in current, while RC circuits respond to changes in voltage.
The time constant for an RL-circuit is equal to L/R. In this case, (0.002 H)/(200 ohm).
A transistor acts like a resistor when Gate is connected to Source.
You need to provide values of resistor and inductor etc to find the phase angle.
When a resistor and an inductor are both connected to an AC supply, the current in the resistor is in phase with the voltage, while the current in the inductor is a quarter-cycle (90 degrees) behind. Supposing they both draw 1 amp on a 12-volt AC supply. The resistor will dissipate 12 watts, while the inductor will dissipate no power. Any power that enters the inductor comes back to the generator in a later part of the cycle. But the current drawn from the supply is 1.414 amps, so this would be a load with a power factor of 0.707.
t = L/R
A circuit in which elements are connected in series.For example in RLC series circuit resistor,inductor and capacitor are connected in series.
The reactance of an inductor depends only on its inductance and the frequency.The voltage and any series components are irrelevant.Z = j 2 pi f L = j 2 pi (100) (0.5) = 314.16 ohmsreactive
Yes, with some difficulty. You can think of an inductor as a kind of "AC resistor"in a way. The higher the frequency of the AC, the more difficulty it has passingthrough the inductor.If you apply AC voltage across an inductor, whereV = voltage of the ACf = frequency of the ACL = inductance of the inductor,then the AC current through the inductor isI = V/2 pi f L
The impedance of a component (inductor or capacitor) will change with frequency - resistor impedances will not. Inductor impedance - j*w*L Capacitor impedance - 1/(j*w*C) L = inductance, C = capacitance, j = i = imaginary number, w = frequency in radians The actual inductance and capacitance does not change with frequency, only the impedance.