well if the bulbs arerated for 110v then 200w but if the bulbs are rated for 220v then only 100w if the bulbs are rated for other voltages then you nedd to do some more calculations.
The total power consumed = 50W.
Calculation:- P=V^2/R
R1=220^2/100
R1=484Ohms.
R2=484Ohms.
R=968Ohms.
I=V/R
I=220/968
I=0.2272A
P=I^2*R
P=(0.2272)^2*968
P=50W.
Lower voltages are required if connected to the low voltage side. The testing facility may not have a gen set large enough to test from the high voltage side.
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
The voltage induced into the secondary winding will be lower than the voltage applied to the primary winding. The primary winding being the winding connected to the supply, while the secondary winding is the one connected to the load.
The voltage is greater than the applied voltage, why?
Induced voltage is generally described by Lenz's Law, which states that the direction of induced voltage (or current) will be such that it opposes the change in magnetic flux that produced it. This means that when an external voltage is applied, the induced voltage acts in opposition to that applied voltage whenever there is a change in magnetic conditions. However, the total voltage in the circuit is the algebraic sum of the applied voltage and the induced voltage, so it can be seen as subtracting from the applied voltage in terms of net effect.
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Light bulbs connected in parallel automatically have "the same voltage applied to them".
The voltage induced into the secondary winding will be lower than the voltage applied to the primary winding. The primary winding being the winding connected to the supply, while the secondary winding is the one connected to the load.
Lower voltages are required if connected to the low voltage side. The testing facility may not have a gen set large enough to test from the high voltage side.
In parallel, each bulb will have full voltage applied across them. However, in series, the voltage across each bulb won't be the same as supply voltage. Thereby, bulbs connected in parallel will glow brighter.
Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
The voltage induced into the secondary winding will be lower than the voltage applied to the primary winding. The primary winding being the winding connected to the supply, while the secondary winding is the one connected to the load.
The load conductor is connected to the load side of the generator breaker. Once the generator is up to speed the load breaker is closed and the voltage is then applied to the load.
The voltage is greater than the applied voltage, why?
To get full brightness, the rated voltage has to be applied across the bulb. When several bulbs are connected in series, the voltage gets devided among these sevral bulbs and correct rated voltage will not be applied acros each bulb, hence the brightness reduces.
Induced voltage is generally described by Lenz's Law, which states that the direction of induced voltage (or current) will be such that it opposes the change in magnetic flux that produced it. This means that when an external voltage is applied, the induced voltage acts in opposition to that applied voltage whenever there is a change in magnetic conditions. However, the total voltage in the circuit is the algebraic sum of the applied voltage and the induced voltage, so it can be seen as subtracting from the applied voltage in terms of net effect.