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No current flows through the battery.

There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.

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15y ago

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What would the current flow be if a short circuit is put across the battery's terminals?

That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.


Why can't you use a multitester as an ohmmeter if it has no battery?

The battery is used by the meter to apply a voltage across the resistance being measured and determine the current which determines the resistance. If there is no battery it can't supply the voltage and can't measure current, so no reading.


What is meant by calculate the equivalent resistance of the circuit from the measured potential difference across the battery and the current through the battery is there a formula for this?

In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.


When a 12 volt battery is connected across an unkown resistance there is a current of 2.5m amphere in the circuit find the value of resistance of the resistor?

4.8 ohms


Why does higher resistance have a larger voltage drop across it?

In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.


A 12 volt battery is hooked up to a circuit and a 3 times 10-3 amp total current is measured what is the total resistance of the current?

Resistance = (voltage across the circuit) divided by (current through the circuit) =12 / (3 x 10-3) = 4 KΩ


Batteries have what current?

Battery maximum current is limited by the internal resistance of the battery. As the current is increased towards this maximum, you will notice the output voltage appear to shink towards zero. What this means is the voltage the battery is capable of supplying is being dropped almost completely across the internal resistance, so no real power is available to use.This internal resistance is dependent on the chemical and physical makeup of the battery.


How calculate unknown resistance?

-- Connect a source of known, small voltage across the ends of the unknown resistance. -- Measure the resulting current through the unknown resistance. -- Divide (small known voltage)/(measured current). The quotient is the formerly unknown resistance.


When two terminals of 4.5 Voltage battery are connected by 100 meters long wire. the current in the wire is 50mA what will be the current from the battery when the wire is shortened 50 meters?

-- The resistance of the wire is proportional to its length. -- When the length is reduced by 1/2 , the resistance is also reduced by 1/2 . -- Reducing the resistance across the battery by 1/2 causes the current to double. -- The new current is 100 mA. (Assumes zero internal resistance in the battery, and that the 4.5 volts doesn't 'sag'.)


When a 12 V battery ie a battery of EMF 12 V is connected across a lamp with a resistance of 6.8 ohms the potential difference across the lamp is 10.2 V Find the current through the lamp?

The potential difference across the lamp is given by Ohm's Law: V = IR, where V is the voltage, I is the current, and R is the resistance. From the given values, 10.2 V = I * 6.8 ohms. Solving for I, we find that the current through the lamp is approximately 1.5 A.


How To Measure Electrical Resistance?

If you put a current of 1 amp through a resistor, the voltage across it is equal to the resistance in ohms. This can also be done with lower currents and then the result must be multiplied up in the right ratio. An ohmmeter, or the ohm scale on a multimeter, uses a battery to supply the current.


How much current 2.2 Megohm?

"Ohm" and its multiples is not a unit of current."Ampere" and its multiples is.The current through a 2.2-megohm resistance is(the voltage across the resistance)/(2,200,000) amperes .