E = U R U = E/R = 460/92 = 5 Amperes
750 watts per horse power20 x 750 = 15,000 watts / 220V = 68A68 amps at 220 volts
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.
Crank the generator excitation up to 480 or down to 460. For calculations I used 480 volts. A 60kW generator at 480 volts will put out, kW x 1000/1.73 x E x (pf(.9)) = 80 amps. It looks like the machine that is to be run off the generator is a dual voltage machine. Not knowing the HP of the machine wire it to the 460 volt connection. The inrush current might be a problem if the HP is high.
depends what the source voltage isone horsepower equals to 746watts (assuming 100% efficiency)746 watts divided by voltage source equals current (amps)AnswerIn countries, such as the USA, where the horsepower is still used as a means of measuring power, it is always used to measure the output power of a motor.So, in order to determine the current drawn by the motor, you will first need to find out its input power. The input power is the output power divided by the machine's efficiency. Once you know its input power, then you can find its current by dividing the input power by the supply voltage. In practise, you will need to use a wattmeter to determine its input power.
Yes, most large motors are three phase. Usually single phase motors only go up to 10 HP. Larger than this and the wire size and contactors used to control the motors becomes extreme. For example a single phase 10 HP motor on 115 volts draws 100 amps. The same single phase motor on 230 volts draws 50 amps. The same 10 HP motor on three phase system draws the following amperage; 230 volts is a 28 amp draw, 460 volts is a 14 amp draw and 575 volts is a 11 amp draw. As you can see the higher the voltage becomes, the smaller the wire feeder size is needed and much smaller size contactor can be used to control the motor.
Ohm's Law: Resistance is voltage divided by current 110 volts divided by 0.4 amperes is 275 ohms.
what is the full load amps for 2.4 hp motor at 460 volts ?
75% of 460 equals 345.
To find the amperage, you can use the formula: Watts = Volts x Amps. Rearranging it, we get Amps = Watts / Volts. Plugging in the values for 3000 Watts and 460 Volts, we get: Amps = 3000 / 460 = 6.52 amps.
To calculate the amperage, use the formula: Amperes = Watts / Volts. In this case, 55 kW is 55,000 watts. So, Amperes = 55,000 watts / 460 volts ≈ 119.57 amps.
460 * 75% is the same as 460 * 0.75, which equals 345.
10% of 460 = 460*10/100 = 46
57.5 x 8 = 460
As a product of its prime factors: 2*2*5*23 = 460
460
460
The power used by the heater can be calculated using the formula: Power = Voltage x Current. In this case, the power would be 460 volts x 5 amps = 2300 watts.