Problem Statement for LCM:
Enter Two digits by a user and get its LCM
Answer:
#include
#include
void main()
{
int x,y,i,j;
clrscr();
printf("Enter Two Digits");
scanf("d",&x,&y);
for(i=1;i<=x;i++)
{
for(j=1;j<=y;j++)
{
if(y*i==x*j)
{
printf("LCM is %d\n",y*i);
i=i+x;
}
}
}
getch();
}
OR
there will be another easy way to solve it...
Answer:
#include
#include
void main()
{
int x,y,i,;
clrscr();
printf("Enter Two Digits = ");
scanf("d",&x,&y);
for(i=1;i<=x*y;i++) {
if(i%x==0&&i%y==0)
{
printf(LCM is %d",i);
break;
}
}
getch();
}
A = 5do{statement;A = A + 1;} while (A < 10)
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
A program can be looped in Python by wrapping the entire program in a for or while loop. If you wish to loop the program a finite amount of times, it can be done like so (x = the amount of times you want it to loop, this can be a number or variable storing a number): for i in range(0,x): [code] If you wish to loop the program infinitely, you can use a simple while loop: while True: [code]
class Abc { public static void main(String[] args) { System.out.println("Hello World!"); } }
With loops, your program is slower.
Not used
//program to find the factorial value f any number using while loop #include<stdio.h> void main() { int i,n,fact=1; printf("Enter the number\n"); scanf("%d",&n); i=n; while (i>=1) { fact=fact*i; i--; } printf("The factorial value=%d",fact); } the above is a program for calculating tha factorial value of any number which is entered by the user
A = 5do{statement;A = A + 1;} while (A < 10)
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
int i=0; while (i++<n) { /*...*/ }
A program can be looped in Python by wrapping the entire program in a for or while loop. If you wish to loop the program a finite amount of times, it can be done like so (x = the amount of times you want it to loop, this can be a number or variable storing a number): for i in range(0,x): [code] If you wish to loop the program infinitely, you can use a simple while loop: while True: [code]
class Abc { public static void main(String[] args) { System.out.println("Hello World!"); } }
The runtime complexity of a while loop in a program is typically O(n), where n represents the number of iterations the loop performs.
#define int main (void){/*Algorithm*/1. First Initialize the number that is Random no2. Using while loop if the person got it, then the loop stop if not the loop continues.}return(0);
The time complexity of using a while loop inside a for loop is O(nm), where n is the number of iterations of the for loop and m is the number of iterations of the while loop.
How do you write a program with do while loop so that the output is 123456 =720
With loops, your program is slower.