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P, the power in kW (kilowatts) is related to V (the supply voltage) and I (the current in amps) by the Power Law:
P = V x I
So, to get the current:
I = P / V
If you have something that uses 5 kW (which is the same as 5000 watts) and the source voltage is 120 V,
then the current drawn in amps = 5000 / 120 = 41.67 amps.
What else can I help you with?
How much surface area in square feet would a 5KW photovoltaic system need?
The area required would depend primarily on the efficiency of the system and on its location. A photovoltaic system works better in a desert in the southwest than in Seattle, Washington.
Circuit diagram for 2kW to 5kW power dc-ac inverters?
motor connection to inverter
What var is drawn by a 5kw induction motor?
You need to know the power factor, the phase angle, or the KVA in order to determine KVAR from KW.Power factor is the cosine of the phase angle between voltage and current, and is also the ratio of KW over KVA.Once you know one of those other things, you simply consider that reactive power factor is the sine of the phase angle between voltage and current, and is also the ratio of KVAR or KVA.It is simple arithmetic from there. You don't even need trigonometry, as I've already given you the ratios.
Load test for 3 phase transformer?
FORMULA1. Input Power =Wattmeter reading × Multiplication factor in WattsWhere, Multiplication factor =2. Output power = VSY × ISY × cosf in Watts.Where VSY - Secondary Voltage in Volts.ISY- Secondary current in Amps.3.Percentage of Efficiency = × 100 %4.Percentage of Regulation = × 100 %Where, VO - No Load Voltage in VoltsVL - Load Voltage in VoltsIMPORTANT!No Load Condition should be observed at the time of startingMeters are checked for proper Type and rating.PROCEDUREConnections are given as per the circuit diagram.The SPST Switch on the Primary side is closed and the DPST Switch on the Secondary side is opened.The Autotransformer is adjusted to Energize the transformer with rated Primary VoltageThe Volt meters and Ammeters Readings are noted and tabulated at No load conditionThe DPST switch on the secondary side is closed.The transformer is loaded upto 130% of the Rated Load, corresponding Ammeters, Voltmeters and Wattmeters readings are noted and tabulated.After the observation of all the readings the load is released gradually to its initial position.The Autotransformer is brought to its initial positionThe Supply is switched off.To find load test on SF transformer you will need:AMMETER - Range (0-10)A - (0-5) A Type MIVOLTMETER (0-150)V - (0-300) V Type MIWattmeter (300V, 5A) - (150V, 5A) Type UPFAuto Transformer 1f, (0-260)VResistive load 5KW, 230VConnecting wires 2.5sq.mm Type Copper
How many 100amp hour batteries do you need to connect to a 240v inverter to produce the same output as a 5kva generator for a period of 2 hours?
I am assuming that your batteries are 12V, also that your (12V - 240V) inverter is rated for 5KW output and it is about 95% efficient. Most big inverters are between 85% - 97%. 5KW from a 12V battery would mean a current draw of about 416A, but since the inverter is only 95% efficient the actual current would be closer to 438A. If you draw 438A for two hours, that's 876AH. Theoretically then, you would need 9 100AH batteries. The problem is that at very high current draw, all batteries AH capacity is less than the rating. You only get the whole 100AH if the current draw is 10A (1/10th the AH rating) or less. Because of that, you would probably need 10 to 12 batteries. If you used 10 batteries, each would source about 44A during full load. You would have to use very large bus bars to equalize the current draw from battery to battery. If the interconnects are too small, the batteries closer to the inverter would be forced to supply more than their equal share of the total current draw, and the ones further away less. It's generally problematic to parallel large numbers of batteries in this way. Don't even consider it unless the batteries are identical (same manufacturer, same part number, same age, same date code). The problem gets even worse when you try to recharge the pack. Suppose you pump 50A of charging current into 10 batteries. Is each battery receiving 5A? Or is one battery with a shorted cell drawing all 50 (and is about to explode...)? There's no way to tell. Even if all batteries were receiving equal charge, it would take your 50A charger almost 40 hours to recharge 10 - 100AH batteries. Ouch. Large industrial UPS systems get around this by using huge 2V cells in series. You can buy 6 - 2V, 1000AH cells, connect them in series to form a 12V, 1000AH battery and avoid all the hassles of parallelling 12V, 100AH batteries. They are not cheap, though. If you go to a battery manufacturer's website, they publish graphs for their batteries that show AH derating versus current draw. All this assumes, of course, that your load is really 5KW. If you are running a smaller load, then obviously your battery count would go down. Finally, we are talking extremely large current and power levels here. If you are not fully qualified to understand and design high current wiring systems, don't try this! 400A of current through a bad connection can do serious damage! Unless you enjoy being sprayed with molten metal from a disintegrating connection, know what you're doing or get a qualified individual to help with/inspect your work. IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS. If you do this work yourself, always turn off the powerat the breaker box/fuse panel BEFORE you attempt to do any workANDalways use an electricians test meter having metal-tipped probes(not a simple proximity voltage indicator)to insure the circuit is, in fact, de-energized.
How do you convert 5kw and 120 voltage to amps?
5000w / 120 volts = 41.66 amps P=E*I transposed to I=P/E
You know the voltage and amps how do you convert to kw?
Power is obtained using the equation: Power (Watts) = Voltage (Volts) x Current (Amps) To convert to Watts to Kilowatts (kW), simply divide by 1000 (or shift the DP left by 3 places). eg. 5000W = 5kW Bringing these together: Kilowatts = ( Volts x Amps ) / 1000
How many amps does a 5000 watt generator supply?
5000 (watts) /120 (volts) = 41.6 amps , but to be safe you should allow 1000 watts margin for peaks, so 4000/120 is 33.3amps, although peaks might sometimes get higher than 5kw
What size of armoured cable to run 400 m to carry 5kw?
This is a voltage drop question. To answer is question the voltage must be stated.
What gauge wire you would use to wire a 5kw heater hvac?
For a 5kW heater HVAC system, you would typically need to use 10-gauge wire to handle the current load safely. It's important to always consult the manufacturer's specifications or a licensed electrician to ensure you are using the correct wire gauge for your specific setup.
Convert 5.0KW to KVA?
5kw = 6.25 kva becoz kva = kw/ pf if we take pf is o.8
How much heat would a 5kW heater produce in Btus per hour?
To convert from kilowatts (kW) to British Thermal Units (BTU) per hour, multiply by 3412. Therefore, a 5kW heater would produce 5 * 3412 = 17060 BTU per hour.
How much surface area in square feet would a 5KW photovoltaic system need?
The area required would depend primarily on the efficiency of the system and on its location. A photovoltaic system works better in a desert in the southwest than in Seattle, Washington.
What size of wire do you need for 5 kw heat strip?
120 15 amp service ? 210 7 amp service ?
What the meaning of 5KW?
1kw electric power
What does 5KW mean?
5KW stands for 5 kilowatts and represents the power output of an electrical device or system. It measures the rate at which energy is consumed or produced.
Does each phase of 5kw 3phase generator give 5kw output?
No! It doesn't matter if you use two legs or three. The output is 5000 watts
