Their relationship is only dependent on the voltage lost across that resistor; voltage equals resistance times current, so increasing the current for a given voltage will require a decrease in the resistance, and vice versa.
The secondary load current will change. This, in turn, will cause the primary current to change (the primary current being the phasor sum of the [IS (Np/Ns)] and the primary current (Io).
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
Ohm's Law says that Voltage = Current x Resistance (Load). Therefore Current = Voltage / Resistance and as resistance decreases current increases and as resistance increases current decreases.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source
As resistance is the ratio of voltage to current, you simply divide the voltage by the current to find the resistance.Strictly speaking however, for a.c. systems, this will give you the impedance, rather than the resistance, of the load. Impedance which, like resistance, is measured in ohms, is the opposition to a.c. current, and is a combination of the load's resistance and reactance.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
The secondary load current will change. This, in turn, will cause the primary current to change (the primary current being the phasor sum of the [IS (Np/Ns)] and the primary current (Io).
The readings on an ammeter indicate the current being drawn by a load in a circuit. This load is basically a resistance to current flow. The higher the resistance, the lower the current. The supply voltage has a direct effect on current flow. The higher the voltage applied, the higher the current will be. So the readings will vary on the ammeter according to fluctuations in load and or resistance of the circuit and the applied voltage.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.
The load resistance in the circuit controls the current flow.
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
Ohm's Law says that Voltage = Current x Resistance (Load). Therefore Current = Voltage / Resistance and as resistance decreases current increases and as resistance increases current decreases.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source
The behaviour you are describing is, in fact, due to the internal resistance of the voltage source.When a voltage source, such as a battery or generator, is not connected to a load, its potential difference is simply the electromotive force (or 'no-load voltage') of that source. When a load is connected, a load current flows not only through the load itself, but also through the internal resistance of the source. This causes an internal voltage drop across the internal resistance, which acts in the opposite sense (i.e. in accordance with Kirchhoff's Voltage Law), or direction, to the electromotive force, thus reducing the voltage available at the terminals. The greater the load (i.e. the lower the load resistance), the greater the resulting load current, and the greater the internal voltage drop -and the lower the terminal voltage.
As resistance is the ratio of voltage to current, you simply divide the voltage by the current to find the resistance.Strictly speaking however, for a.c. systems, this will give you the impedance, rather than the resistance, of the load. Impedance which, like resistance, is measured in ohms, is the opposition to a.c. current, and is a combination of the load's resistance and reactance.