Resistance does not change frequency.
Frequency cannot be changed without very sophisticated equipment, often called Variable Frequency Drive, or VFD, which is used in motor starters today.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
The capacitance counter acts the inductivity (decreases it) without impacting the resistivivity, thus increasing the power factor, or resistivity / inductivity ratio.
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
Any devices that are added to a circuit and need the full line voltage to operate, are added in parallel to any other load devices or fixtures in the circuit.
The total current decreases.According to the Ohm's law the current & the resistance are inversely proportional so when we put a load in series with the existing load, the resistance of the circuit increases therefor the current decreases.
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When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Adding more branches to a parallel circuit decreases the overall resistance of the circuit. This leads to an increase in the total current flowing through the circuit as each branch provides an additional pathway for the current to flow. This results in a decrease in the total resistance and an increase in the overall current of the circuit.
Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.
It is unclear what type of circuit you are referring to, so I'll give both answers.parallel, current increases until too many bulbs have been added, then circuit breaker pops and current drops to zero.series, current decreases and all bulbs dim.
Current will be decreased because of the resistance of the ammeter added to the circuit's resistance. In other words total resistance increases.
First, capacitance is the resistance of something to a change in voltage. And capacitance exists anywhere there is a conductor that is insulated from another conductor. With that definition, anything has capacitance. And that's correct. It is also the key to understanding the capacitance in high frequency (radio frequency or RF) circuits. The fact that a circuit had conductive pathways and component leads and such means that there is a lot of little bits of capacitance distributed around the circuit. The capacitance is already there; it isn't "added" later as might be inferred. Normally, this bit of capacitance isn't a problem. But at higher and higher frequencies, it is. Remember that the higher the frequency of an AC signal, the better it goes through a given cap. So at higher and higher frequencies, the distributed capacitance in the circuit "shorts the signal to ground" and takes it out of the circuit. The RF is said to be coupled out of the circuit through the distributed capacitance in that circuit. The higher the frequency a given circuit is asked to deal with, the more signal will be lost to this effect. It's just that simple. Design considerations and proper component selection minimize the distributed capacitance in a circuit.
In general, the lower the frequency of operation, the more weight must be added to the core laminations to avoid magnetic field saturation. This increases the size and weight of the transformer as the frequency decreases.
Yes, the current split in parallel circuits does affect the overall resistance in the circuit. In a parallel circuit, the total resistance decreases as more branches are added because the current has multiple paths to flow through, reducing the overall resistance.