The equation you are looking for is I = W/E. Amps = Watts/Volts.
Load!
The maximum current that can be drawn from a voltage source is dependent on the impedance of that source, the impedance of the connections to the source, and the energy available from that source.
p=r*i
maximum demand is measured in kva because current drawn is dependent on power factor for the same load and current drawn is calculated with kva
at lower power factor current drawn by load is high and at higher pf the current drawn is less...
If they are in series, the total resistance is 150 ohms so the current is 120/150 amps. If they are in parallel, the current is 120/100 plus 120/50 amps.
Load!
load
It is a the current drawn by the application that is connected to the power source
A 6000 watt toaster oven, if one could exist, would pull 50 amperes from a 120 volt supply.The question is unrealistic, because the maximum branch current for a normal circut would be about 16 amperes, using the 80% rule, and that would produce about 2000 watts.
No tangent No tangent
The maximum current that can be drawn from a voltage source is dependent on the impedance of that source, the impedance of the connections to the source, and the energy available from that source.
An ethanol level is typically drawn in a gray-top tube containing potassium oxalate and sodium fluoride as preservatives.
nothing..............
Basically, Power = Current*Voltage Current = Power/Voltage Current = 15/120 Current = 0.125A or 125mA
None
The mgnetic inrush current is the current drawn by the transformer when power is applied to the primary winding