no, the circuit won't complete
the circuit would not be complete. the lightbulb would not light or the buzzer would not buzz
A circuit must have three basic components to make electricity flow. 1. Source of power or electricity. 2. Wires, switches and conductors through which the current can flow. 3. And finally a load to complete the circuit.
a complete circuit is a circuit through which a current can flow(see closed circuit)A complete circuit is almost like a circle. Energy flows through this circle in order to make the light bulb light.A circuit that has a power source, a load such as a light or motor to power and a ground point.A complete circut is a circut with no gaps.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
This question would be easier to answer if the type of IC was specified.But generally, there are 3 reasons an IC will not work:1. It is broken. If a large voltage or shock has been applied to it, or the power hooked up to it in reverse, an IC will usually burn out. This may or may not be accompanied with the release of the Magic Blue Smoke. (http://en.wikipedia.org/wiki/Magic_smoke)2. Your power supply is dead or not outputting enough voltage. If the voltage supplied is too low for the IC to use, it may not function properly or at all. Check the power supply.3. The circuit the IC is in is broken. Check all the wires/solder points. Test the IC in a known working circuit.
If the bulb's filament is broken, the whole circuit becomes open. If the bulb is in a series circuit or is the only bulb, the electricity would no longer flow. If the bulb is in a parallel circuit, along with other bulbs, then only the blown bulb would go out, and the other bulbs would still work.
When a bulb fuses the circuit is broken if it is on a serial circuit. If the bulb is on a parallel circuit, only the fused bulb will go out, any other bulb would remain lit. On a serial circuit, until the bulb is replaced by a new one, the circuit is not able to be used.
A voltmeter connected across the broken (open) filament of a light bulb reads the full voltage of the power supply whether the bulb is in a series or parallel circuit. -- In a series circuit with other components in series with the bulb, this reading tells you that at least one of the components is open, possibly the filament. -- In a parallel circuit with other components in parallel with the bulb, or with the bulb connected directly to the power supply, this reading tells you nothing ... the voltmeter reads the full power supply voltage whether the bulb is open or good. The voltmeter isn't a very helpful measurement to identify an open filament. An ohmmeter, with the power to the circuit turned off, is much more helpful.
In a series circuit, all bulbs are necessary to complete the circuit. If one bulb goes out, the circuit is broken, so none of the bulbs would light up.
Because the filament is in effect a resistor. Copper is too good a conductor to provide resistance to the current, and would simply allow the current to complete the circuit. The light is generated by the filament glowing as it heats up in resistance to the current. Tungsten is a much better resistor.
the circuit would not be complete. the lightbulb would not light or the buzzer would not buzz
To get an open circuit to work and light a light bulb, turn the switch on. Or hardwire it to power up the lamp. If the battey or other power source is good, and so is the lamp, make sure all the connections are good and that the conductor (wire) isn't broken. With all the components in good shape and properly connected, the light should be glowing.
There is no element to heat to complete the circuit. Another example would be magnetic induction lighting.
No paper is an insulator.
Maybe, but not sure info would be useful. You can use ohmmeter to check that a tube's filament is intact. Broken/burned-out filament is most likely reason for dead tube.
A circuit is complete whenever current can flow from the battery (or what is producing current), through the circuit, and back to the battery. A complete circuit could contain just a battery and one wire. An incomplete circuit could be a battery with a wire attached to just one terminal, because current cannot flow all the way through the circuit in this case (i.e. cannot flow through the battery). note: not all elements in a circuit may have current flow in a complete circuit. For instance, a light bulb may be shorted but you still have a complete circuit.
No power is used. The lamp in the light fixture is the load of the circuit. The load resistance is what makes the current flow. When the current flows through the filament's resistance, heat and light are generated. With no lamp in the fixture, the circuit's voltage potential is still at the socket contact points and if touched could cause you a shock. This is a good reason to shut the fixture off at the switch when removing the burnt out bulb and replacing it with a new one.