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No. This would mean more power is used than is provided - an impossibility. It is possible that you may not be accounting for a power source in your circuit, or have the actual source modelled incorrecty.

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A 14point1 V battery is connected to a 142 resistor Neglecting the internal resistance of the battery calculate the power dissipated in the resistor Answer in units of W?

In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)


A can be used to reduce the current in a circuit?

A resistor.


What power is dissipated if 800v is applied across a 10 ohm resistor?

The power dissipated by a 10 ohm resistor with 800v across it is 64 kw.Ohm's law: current is voltage divided by resistancePower law: power is voltage times current, so power is voltage squared divided by resistanceDon't even think about trying this. 64 kw is a lot of power. The resistor will probably explode, or catch fire. At best, the 80 amps required will trip your circuit breaker, if you are lucky.


What happens when you add a resistor to a series circuit with a light bulb?

As you add more bulbs to a series circuit that means that the bulbs are in series to one another, therefore the total resistance is the sum of the individual resistance of the bulbs. If you add bulbs of the same resistance,then the rate at which the resistance changes will increase in a constant manner provided the current source is not altered. For instance if the bulb you are using is rated 20v,60w, then the current passing via the bulbs in series is the square of the voltage divided by the power in this case the current is approximately 7amperes.


What is series dropping resistor?

A series dropping resistor is a resistor that limits the amount of current flow in a circuit.

Related Questions

How is the energy dissipated by the resistor in an RC circuit calculated?

The energy dissipated by a resistor in an RC circuit is calculated using the formula: Energy 0.5 C V2, where C is the capacitance of the circuit and V is the voltage across the resistor.


How do you measure current without an amp meter?

Depends on the current. Put a resistor in-line with the current, then measure the voltage across the resistor. V=RI. So, divide the measured voltage by resistor value. Be careful with the size of the resistor, as Power dissipated in a resistor is R*I^2 or V^2/2. So, a 1-Amp current into a 1 Ohm resistor will result in a 1Watt power dissipated in the resistor. If it's too small, it'll burn. Also, notice that if you do that, you haven't measured the current in the original circuit. You've measured the current when an extra resistor is installed in the original circuit, and that's different.


What does a resistor do in an ampliflyer circuit?

what does a resistor in an ampliflyer circuit


Why resistor should disconnected from the circuit when measured the value of resistor?

if not disconnected you will measure the resistance of the circuit in parallel with the resistor.


A 14point1 V battery is connected to a 142 resistor Neglecting the internal resistance of the battery calculate the power dissipated in the resistor Answer in units of W?

In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)


Five series resistors each dissipate 50 mW of power What is the total power?

AS:total power = P1 + P2 + P3 + .......so,total power = 5(50mW)= 0.25Wtotal power dissipated by the five resistors is 0.25W.


What would happen to the power dissipated in the voltage divider?

The power dissipated in a voltage divider circuit is given by the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance of the resistor. If the resistance in the voltage divider circuit is increased, the power dissipated in the circuit will decrease. This is because as resistance increases, the current flowing through the circuit decreases, leading to less power being dissipated as heat in the resistors.


A can be used to reduce the current in a circuit?

A resistor.


What parts of a circuit acts as a resistor?

Any part of a circuit that has a voltage drop across it is a resistor.


What power is dissipated if 800v is applied across a 10 ohm resistor?

The power dissipated by a 10 ohm resistor with 800v across it is 64 kw.Ohm's law: current is voltage divided by resistancePower law: power is voltage times current, so power is voltage squared divided by resistanceDon't even think about trying this. 64 kw is a lot of power. The resistor will probably explode, or catch fire. At best, the 80 amps required will trip your circuit breaker, if you are lucky.


What does the variable resistor do in a circuit?

It is used to vary the voltage/current flow in a circuit.


When you have watts in a series circuit do you add up the total or is it the reciprocal?

The power dissipated by the complete circuit, no matter whether it's a series or parallel one, is the simple sum of the power dissipated by each component of the circuit.