An int
typically occupies 4 bytes of memory in most programming environments, including languages like C, C++, and Java, assuming a standard architecture. Therefore, an int
variable, such as int a = 100;
, will occupy 4 bytes. However, this can vary depending on the specific programming language and architecture used, so it's always a good practice to check the documentation for the language in question.
Int: 4 bytes Float: 4 double: 8 char: 1 boolean: 1
The storage size of an int in C is loosely defined, and may be either 2 bytes or, more commonly, 4 bytes. Whether or not it is defined as const won't affect the size.
The sizeof long int is platform-dependent, often 4 bytes or 8 bytes.
It depends on the type of integer (such as long, short, int and char) and the specific implementation of C++. The only guarantee is that a char must occupy one byte (sizeof(char)==1). An int is typically 32-bits (4 bytes), but only sizeof(int) can tell you for sure.
for C: sizeof (int), often 2 or 4 bytefor Java: 4 byte
An int typically occupies 4 bytes in memory on most modern systems, including those using the C and C++ programming languages. However, this can vary depending on the system architecture and the specific compiler settings. In some environments, such as certain embedded systems, an int might occupy 2 bytes or even 8 bytes. It's important to check the specifics of the platform being used.
32 bits or 4 bytes and an int is not an address, it is a primitive so it directly access the data without a reference.
Int: 4 bytes Float: 4 double: 8 char: 1 boolean: 1
The storage size of an int in C is loosely defined, and may be either 2 bytes or, more commonly, 4 bytes. Whether or not it is defined as const won't affect the size.
The sizeof long int is platform-dependent, often 4 bytes or 8 bytes.
It depends on the type of integer (such as long, short, int and char) and the specific implementation of C++. The only guarantee is that a char must occupy one byte (sizeof(char)==1). An int is typically 32-bits (4 bytes), but only sizeof(int) can tell you for sure.
sizeof (int) will tell you (in bytes). It's often 2, 4 or 8 bytes.
in java, char consumes two bytes because it uses unicode instead of ascii. and int takes 4 bytes because 32-bit no will be taken
for C: sizeof (int), often 2 or 4 bytefor Java: 4 byte
As 4 adjacent bytes.
printf ("sizeof (int) is %d bytes", (int)sizeof (int)); Most likely it will be 2 or 4.
You mean how many bytes? It is sizeof (int) -- usually 4, on archaic platforms 2 (TurboC).