To arrange numbers in ascending order using Java, you can utilize the Scanner
class to read input from the user and then sort the numbers using an array. Here's a simple example:
import java.util.Arrays;
import java.util.Scanner;
public class AscendingOrder {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the number of elements: ");
int n = scanner.nextInt();
int[] numbers = new int[n];
System.out.println("Enter the numbers:");
for (int i = 0; i < n; i++) {
numbers[i] = scanner.nextInt();
}
Arrays.sort(numbers);
System.out.println("Numbers in ascending order: " + Arrays.toString(numbers));
scanner.close();
}
}
This program collects a specified number of integers from the user, sorts them using Arrays.sort()
, and then displays the sorted list.
To write a C++ program to display the student details using class and array of object.
public class BubbleSortAscendingOrderDemo { public static void main(String a[]) { //Numbers which need to be sorted int numbers[] = {23,5,23,1,7,12,3,34,0}; //Displaying the numbers before sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } System.out.println(); //Sorting in ascending order using bubble sort bubbleSortInAscendingOrder(numbers); //Displaying the numbers after sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } }
Writing a C program that uses dynamic memory allocation to sort names in ascending order is a typical computer science assignment. To write this program, you must be in UNIX.
Use a looping structure. The first step initialises a loop control variable, n, to zero. You then begin the loop by processing the nth element from the array (the process may be a simple print statement). You then increment n. Finally, you test the value of n; if it is less than 10 you start a new iteration of the loop, otherwise you proceed to the end of the flowchart.
No, "Hello world" is typically the first program assignment in introductory computer programming classes as it is trivial to write and almost useless.
sorry
the following program will display all numbers given in the array in ascending order #include<stdio.h> void main() { int i,h,p; int numbers[10]={5,8,3,2,6,7,9,4,1,10}; for(p=0;p<=8;p=p+1) { for(i=0;i<=8;i=i+1) { if(numbers[i]>numbers[i+1]) { a=numbers[i]; numbers[i]=numbers[i+1]; numbers[i+1]=a; } } } for(i=0;i<=9;i=i+1) { printf("%d ",numbers[i]); } }
To write a C++ program to display the student details using class and array of object.
I know how to do this and you need to know how to do this. Why don't you do your best at writing this program and if it does not work then ask for help. You will not learn anything if I give you the answer.
#include<iostream> int main() { for (int i=0; i<100; ++i) std::cout<<i<<std::endl; }
public class BubbleSortAscendingOrderDemo { public static void main(String a[]) { //Numbers which need to be sorted int numbers[] = {23,5,23,1,7,12,3,34,0}; //Displaying the numbers before sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } System.out.println(); //Sorting in ascending order using bubble sort bubbleSortInAscendingOrder(numbers); //Displaying the numbers after sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } }
main (){int i,j,a,n,number[30];printf ("Enter the value of N\n");scanf ("%d", &n);printf ("Enter the numbers \n");for (i=0; i
das
Writing a C program that uses dynamic memory allocation to sort names in ascending order is a typical computer science assignment. To write this program, you must be in UNIX.
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Use a looping structure. The first step initialises a loop control variable, n, to zero. You then begin the loop by processing the nth element from the array (the process may be a simple print statement). You then increment n. Finally, you test the value of n; if it is less than 10 you start a new iteration of the loop, otherwise you proceed to the end of the flowchart.
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