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The relationship of the bandwidth required for double-sideband emitted carrier AM to the bandwidth of the modulating signal of?
In Amplitude Modulation (AM), specifically in the case of Double Sideband Suppressed Carrier (DSB-SC) or Full Carrier (DSB-FC) AM, the required bandwidth is twice the bandwidth of the modulating signal. If the modulating signal has a bandwidth of B Hz, the bandwidth required for AM would be 2B Hz. This is because both the upper and lower sidebands of the carrier wave are utilized in the modulation process, each consuming bandwidth equivalent to the original signal.
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What is the relationship between the minimum bandwidth required for an FSK system and the bit rate and the mark and space frequencies?
In Frequency Shift Keying (FSK) systems, the minimum bandwidth required is influenced by the bit rate and the mark and space frequencies. According to Carson's Rule, the bandwidth can be approximated as twice the sum of the frequency separation (the difference between mark and space frequencies) and half the bit rate. Therefore, as the bit rate increases, the required bandwidth also increases, necessitating wider frequency separation between the mark and space frequencies to maintain signal integrity. This relationship ensures that the FSK system can effectively transmit data without interference or distortion.
How do you calculate minimum bandwidth that a signal requires PSK?
To calculate the minimum bandwidth required for a Phase Shift Keying (PSK) signal, you can use the formula: ( B = \frac{R}{2} ) for binary PSK (BPSK), where ( B ) is the bandwidth and ( R ) is the data rate in bits per second. For higher-order PSK, such as QPSK or 8-PSK, the bandwidth can be calculated as ( B = \frac{R}{k} ), where ( k ) is the number of bits per symbol. Additionally, considering the required filtering and the Nyquist bandwidth, the actual bandwidth may be slightly wider to accommodate spectral shaping.
When you do modulation in time domain you get modulated waveform of modulating signal information and carrier. How can you recognize the upper and lower side bands in time domain modulated waveform?
You need modulation signal(carrier) which is a required signal in order to make envelope of time domained signal(target signal). The modulating signal is imposed on modulation signal.This creates envelope of waveform which is modulated(desired) signal. Now, the desired signals uper and lower sideband of signal strictly depends on modulation signal's bandwidth. Max. peak of that signal is uper sideband and min. peak is lower sideband for this modulated signal.
What is bandwidth required for AM signal?
With full double sideband AM the bandwidth of the modulated signal is twice that of the baseband information signal. With suppressed carrier single sideband AM the bandwidth of the modulated signal is identical to that of the baseband information signal. With vestigial sideband AM the bandwidth of the modulated signal is somewhere between the above two cases, depending on how much of the vestigial sideband is included.
Why the entire frequency range of 20hz-20khz is not used in telephony?
Because it is not necessary, and providing that bandwidth would increase cost and complexity. While the full range of 20Hz-20KHz is required for proper rendering of music, telephony, by standard, only requires a 3.5KHz bandwidth. You can hear and understand the spoken voice with only this range. You do not need the extended musical range.
What is bandwidth required for e-gov application?
How much bandwidth required for e-gov application?
What are the disadvantages of fsk?
required larger bandwidth
What is the relationship between the minimum bandwidth required for an FSK system and the bit rate and the mark and space frequencies?
In Frequency Shift Keying (FSK) systems, the minimum bandwidth required is influenced by the bit rate and the mark and space frequencies. According to Carson's Rule, the bandwidth can be approximated as twice the sum of the frequency separation (the difference between mark and space frequencies) and half the bit rate. Therefore, as the bit rate increases, the required bandwidth also increases, necessitating wider frequency separation between the mark and space frequencies to maintain signal integrity. This relationship ensures that the FSK system can effectively transmit data without interference or distortion.
Is a headlight required on a motorcycle in Colorado?
On Road: Yes. Modulating Headlights are OK to use during the day, also.Off Road: Required to ride after dark.
Which is needed to implement to guarantee the required bandwidth for VoIP?
QoS
How much bandwidth is required to listen to Essex FM online?
There is no information available as to how much bandwidth Essex FM online radio takes. It is not as much as required, but how much it takes up is what the worry is for. Most internet providers have a limit as to how much bandwidth you are allowed to use in a month.
Advantages of large bandwidth?
A very usefull advantage is the exchange of SNR(signal to noise ratio) with Bandwidth... as on increasing the bandwidth the power required for transmission get reduced to a great extent.. is given by the formula SNR2 ~ (SNR1) B1/B2 AS we can see on increasing the bandwidth the SNR is reduced greatly
Given a bit rate of 1200 bps what is the minimum required bandwidth?
600 Hz
How much minimum bandwidth is required for multiplexed channel?
The minimum bandwidth required for a multiplexed channel depends on the number of channels being multiplexed and the bandwidth of each individual channel. In general, the total minimum bandwidth needed is the sum of the bandwidths of all the channels being combined. For example, if you are multiplexing four channels, each requiring 1 MHz, a minimum bandwidth of 4 MHz would be necessary. Additionally, some multiplexing techniques may require guard bands to prevent interference, which would increase the total bandwidth requirement.
How do you calculate minimum bandwidth that a signal requires PSK?
To calculate the minimum bandwidth required for a Phase Shift Keying (PSK) signal, you can use the formula: ( B = \frac{R}{2} ) for binary PSK (BPSK), where ( B ) is the bandwidth and ( R ) is the data rate in bits per second. For higher-order PSK, such as QPSK or 8-PSK, the bandwidth can be calculated as ( B = \frac{R}{k} ), where ( k ) is the number of bits per symbol. Additionally, considering the required filtering and the Nyquist bandwidth, the actual bandwidth may be slightly wider to accommodate spectral shaping.
When you do modulation in time domain you get modulated waveform of modulating signal information and carrier. How can you recognize the upper and lower side bands in time domain modulated waveform?
You need modulation signal(carrier) which is a required signal in order to make envelope of time domained signal(target signal). The modulating signal is imposed on modulation signal.This creates envelope of waveform which is modulated(desired) signal. Now, the desired signals uper and lower sideband of signal strictly depends on modulation signal's bandwidth. Max. peak of that signal is uper sideband and min. peak is lower sideband for this modulated signal.
Find the minimum bandwidth for FDM five sources each requiring 400Hz 200Hz guard band per channel?
no of sources: 5 bandwidth required for each source= 400 Hz no of guard times= 5 bandwidth of each guard time = 200 Hz minimum bandwidth = 5 *400 + 5*200 Hz
