the answer would be 48 m/s
A good antenna for general area coverage that features a doughnut pattern and extends horizontal distance in a 360-degree radius is a dipole antenna. Dipole antennas are typically used for omnidirectional coverage, providing consistent signal strength in all horizontal directions while minimizing vertical range. Another option is the omnidirectional vertical antenna, which also offers similar coverage characteristics. These antennas are commonly used in applications like broadcasting and wireless communication.
The answer depends on whether the cross sectional radius/diameter are doubles or the cross sectional area is doubled.
If: A=Horizontal distance betwen ends (at same height) B=Depth of catenary C=radius of curvature at lowest point L=length along catenary M=Mass per unit length Tm=Tension at ends of catenary To=Tension at lowest point. (Also horizontal component of tension at any point) Then: C=To/M, and B=C(cosh(A/2C)-1)
this is question related to the strength of materials rather than the hydraulics the basic equation for the stresses in thick walled cylinders will give you the pressure at which the respective hydraulic cylinder can be operated. for radial stress=((piri2 )/ (r02 -ri2)) * ((1 - (ro2/r2))) where pi is the internal pressure of the cylinder ri is the internal radius of the cylinder. r0 is external radius of the cylinder. r is the radius of the point you have selected on the cylinder (this is mostly ri because it is the point were high stress is felt .apparently this formula gives the value of radial stress at point selected by you that is the 'r' value) for tangential stress=((piri2 )/ (r02 -ri2)) * ((1 + (ro2/r2))) adding the 'tangential stress' and the 'radial stress' would give you the value of the 'axial stress' this along with some 'factor of safety' value can determine the operating pressure of the hydraulic cylinder or in this case the internal pressure of the cylinder.
describes the relationship by which the amount of tension generated in the wall of the ventricle (or any chamber or vessel) to produce a given intraventricular pressure depends of the size (radius and wall thickness) of the ventricle.
They are all circles. The vertical and horizontal have the same radius as the ball while the angled cross section has a smaller radius.
The height of a horizontal cylinder is 2 times its radius.
The radius of a cylinder is half the thickness of its circular cross section.
As the afferent radius increases, glomerular pressure increases as well. This is due to the increased volume of blood flowing into the glomerulus, resulting in a higher pressure exerted on the glomerular capillaries.
196 rads/s
True!
True
True
True
If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32) Therefore the cross sectional area is pi*(R2 - 32) square units.
Relationship between radius and area of a circle is nonlinear. Area = pi * radius^2, so it is like a quadratic. If you graphed radius on the horizontal, and area on the vertical, it would be a parabola (actually a half of a parabola, since you cannot have a negative radius).
If R is the horizontal radius and S is the vertical radius, the Cartesian formula for an ellipse is:f(x) = plusminus (S/R)(sqrt(R2-x2))