It means that the loudspeaker maker tells you that his loudspeaker builds an input impedance (load impedance) of Zload = 4 to 8 ohms. In audio we use always voltage matching and so the amplifier output should have a source impedance of smaller Zsource = 0.1 ohm. Scroll down to related links and look for "Damping Factor".
wire two 8 ohm speakers in a parallel circuit!
Purely additive. 2+3+4+5+6=20.
16 Ohms. Yes 16 ohms in series. 4 ohms in parallel
5 ohms in parallel with 20 ohms is 4 ohms. 4 ohms across 200 volts is 50 amperes. However, resistance is a function of temperature, so the 4 ohms will probably be higher, reducing the current. How much depends on the temperature coefficient of the loads.
The speaker you connect to those terminals needs to be 4 ohms or greater.
this is range of 4 ohms resistance in an electrical device. Ohms is a measure of resistance in electrical qualities. Circuits and devices are rated , or measured for there resistance in ohms to meet a designed electrical need. Is this related to a speaker?
The difference between 2 ohms and 4 ohms is 2 ohms.
2 ohms of resistance
Sure, If you mean your stereo has 4 ohm output and using 16 ohm speakers. The volume will be reduced somewhat by doing this, but it won't harm the stereo. If you have 4 ohm speakers and stereo is designed for 16 ohms you can do it ,but the amp will run hot and you may suffer damage at high volume to the amp.
Ohms is a measure of impedance (resistance), not volume.
There are 4 ohms
It seems you mean a tera-ohm which is a million million.See related links below
Car stereos are designed for 4-8 ohms loads unbridged (8 ohms bridged). So wire it for 4 ohms. If you use a separate amp for the speaker then refer to the amp's documentation - most are designed to operate with standard 4 ohms unbridged and may also have provision for 2 ohms unbridged (or 4 ohms bridged).
It has to do with the load on the amplifier, you can't hear the difference.
wire two 8 ohm speakers in a parallel circuit!
Purely additive. 2+3+4+5+6=20.
Purely additive. 2+3+4+5+6=20.