Ohms is a measure of impedance (resistance), not volume.
no
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
The current in the circuit will depend on how the three resistors are wired. Series? Parallel? Series parallel? With the resistors in series, 3, 2 and 4 ohms will add to 9 ohms. As I = E/R, I = 9 V / 9 ohms = 1 A. With the resistors in parallel, the 3, 2 and 4 ohm resistors will draw 3 A, 4.5 A and 2.25 A respectively, and the total current will be the sum of the branch currents, or 3 A + 4.5 A + 2.25 A = 9.75 A. There are 3 different series parallel circuits possible, and more investigation will be necessary to solve for them.
It has to do with the load on the amplifier, you can't hear the difference.
Resistivity of Copper = 1.68x10^-8 radius of wire = 1.7x10^-3m/2 = 8.5x10^-4 A =pi*(8.5x10^-4)^2 = 2.310^-6m^2 Plugging in the numbers: R = 2.6x10^-2 = .026 Ohms
In a parallel circuit, the total resistance is the inverse of the total of 1 over the value of the first resistor plus 1 over the value of the second resistor. Said another way, if you take 1 over the value of R1 plus 1 over the value of R2, and then take 1 over that, you will find Rtotal. So let's do that. 1/10 + 1/2 = 1/10 + 5/10 = 6/10 1 divided by 6/10 = 10/6 = 1 2/3 ohms for the total resistance. As a quick check, in any parallel network where a group of resistive elements are all connected in parallel, the total resistance will be less than the value of the smallest one. The smallest one in this case is 2 ohms, so we are good to go by that simple check.
The difference between 2 ohms and 4 ohms is 2 ohms.
2 ohms of resistance
the watts for 2 ohms is more than 4 ohms. depending on the ohms your speakers take up and the wattage the speakers use, tells you what size amp you need.
It is the impedence (coil resistence)normally sub component (drivers)are in 8 ohms impedence.2 in parralel is 4 ohms and 4 in parralel makes it 2 ohms.
Purely additive. 2+3+4+5+6=20.
Purely additive. 2+3+4+5+6=20.
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
the ohm is a unit of measurement based off of someones last name. When used in subwoofers, for example 4 ohms or 8 ohms, it actually determines the amount of watts the speaker needs. Like if two identical subwoofers were taken and one was 4 ohms and one 8 ohms and applied say 150 watts to each of them, the 4 ohm would be louder because ohms are the speakers resistance and the lower the ohms the less amount of power it takes for the subwoofer to reach a specific loudness. That's why professional huge subwoofers may be one ohm, because an amplifier that has less power than the sub could still power it because since its one ohm, the 500 watt amplifier at 4 ohms could be 1500 watts at 1 ohm.
135 ohms new, and will function properly down to 114 ohms. The chart in the '86-'87 book shows: Empty=110 ohms +/- 7 ohms Full=3 ohms +/- 2 ohms 1/2 full= 32.5 ohms +/- 4 ohms
Car stereos use 12V which is lower than the 30V used in home stereos. Power = voltage^2/Resistance. To get the same power with lower voltage the speaker resistance is lower. Most home speakers are now 4 Ohms and car speakers are now 2 Ohms.
That's tricky given that a speaker with better sensitivity will be louder than a less sensitive one for the same power. An 8 ohms speaker with a sensitivity of 93db/W/m will be twice as loud as a 4 ohms speaker rated at 90db/w/m (both fed 1W of power, that's 2.83V for 8 ohms and 1.415V for 4 ohms). The net result is that for the same loudness the 8 ohms speaker will put less load on the stereo or amp.So for 93db/W/m, the 8 ohms speaker requires 2.83V, so draws 0.35A. The 4 ohms speaker will need 2.83V instead of 1.415V for the same loudness (it is 3dB less efficient). So it draws 0.7A at 2.83V. Thus the amp runs hotter.In summary car systems are designed for 4 ohms and speakers are quoted for loudness at 2.83V - that makes them appear louder than 8 ohms speakers. This is wrong since loudness is not measured with voltage but with watts. So whenever you see a 4 ohms driver quoted for 2.83V simply reduce 3dB from the loudness (SPL) value advertised to find its actual rating and then get the speaker that has the highest SPL rating that you can afford. That way you will get more loudness without having to turn up the volume knob all the way to max.
Which of what following? The inductance of the coil must be higher than the resistance of the coil, since the supply is providing 200*10 = 2000VA. 2000VA =sqrt[ (I^2 * R)^2 + (I^2 * L)^2] 4000000VA = I^4*R^2 + I^4*L^2 400 = R^2 + L^2 and 1000Watts = R*I^2, so R = 10 ohms 400 = 100 + L^2 L = 17.3 ohms