If voltage remains constant and resistance is increased, the amperage will decrease per Ohm's Law.
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
if we remove a resistor from the parallel connection the effective resistance value will be increased.
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
In a simple circuit, lowering the voltage will not cause the resistance to do anything. Lowering the voltage will, however, cause the current to also lower.This ignores temperature coefficient. If there is substantial power involved, a typical bulb, for instance, will grow cooler and its resistance will decrease when you lower the voltage, but that is usually a small effect.
If you increase the number of bulbs in a circuit, the resistance in the circuit will increase, causing the motor's speed to decrease. If you decrease the number of bulbs, the resistance in the circuit will decrease, causing the motor's speed to increase.
To increase (current) flow in a circuit you increase voltage (or decrease resistance). Ohm's Law: Current = Voltage divided by resistance
As long as the voltage between the ends of the circuit remains constant, the current through the circuit is inversely proportional to the total effective resistance of the circuit.
If voltage remains constant and resistance is increased, the amperage will decrease per Ohm's Law.
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
When you increase the resistance in a circuit, the current (amps) in the circuit will decrease. This is because Ohm's Law states that current is inversely proportional to resistance, so as resistance increases, current decreases.
Ways to reduce electrical resistance: increase the diameter of the conductor, decrease or increase the temperature of conductor (depending on its thermal characteristics), decrease the length of the conductor. A change in the material out of which the conductor is made can decrease resistance, too. And there is the phenomenon of superconductivity. In a simple circuit the resistance can be lowered by adding resistors in parallel. The total circuit resistance will then decrease. You can also reduce resistance by substituting resistors of lower value, or by adjusting a potentiometer, or pot, to a lower value.
Increase the resistance (ohms) Decrease the voltage (Volts)
if we remove a resistor from the parallel connection the effective resistance value will be increased.
An increase in voltage or a decrease in resistance will cause an increase in current flow in a simple series circuit. This is because current is directly proportional to voltage and inversely proportional to resistance according to Ohm's Law.
For a circuit to get cold, the voltage across the circuit must decrease, and the resistance within the circuit must increase. This decrease in voltage reduces the energy flowing through the circuit, while the increase in resistance limits the flow of current, resulting in less heat generation. By manipulating these two factors, the circuit can be cooled down effectively.
If additional resistance is connected in parallel with a circuit the supply voltage will decrease?