if R4 is the only resistor (the load), then the drop would be the same as the energy source
You'll see a voltage drop across a resistor if current is flowing through it. It only has to be a part of a complete circuit, i.e. one in which current is flowing.
For voltage drop calculation you must use the current of the load and the distance of the load from the supply source. The circuit breaker is then used to limit the current to the rating of the wire that feeds the load.
The percentage voltage drop is calculated using the formula: [ \text{Percentage Voltage Drop} = \left( \frac{V_{drop}}{V_{supply}} \right) \times 100 ] where ( V_{drop} ) is the voltage drop across the load or conductor, and ( V_{supply} ) is the supply voltage. Measure the voltage at the load and subtract it from the supply voltage to find ( V_{drop} ). Then, apply the formula to express the voltage drop as a percentage of the supply voltage.
If a swing has a working load of 300 pounds and the rotation hook has a working load of 1000 pounds, what is the maximum weight of a person that would be allowed on the swing?
High resistance on the feeder to the load will cause voltage drop at the load end of the circuit. If this is happening, do the calculations for voltage drop, using the amperage of the load, voltage of the load, the size of the wire feeding the load and the distance from the distribution panel to the load.
The load on a crane hook changes based on several factors, including the weight of the lifted object, the angle of the load, and any dynamic forces during lifting or lowering. As the crane hoists or lowers the load, the tension in the hook will fluctuate due to these variables. Additionally, if the crane swings or experiences wind, the load's effective weight on the hook can vary, impacting overall stability. Proper calculations and monitoring are essential to ensure safe lifting operations.
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if R4 is the only resistor (the load), then the drop would be the same as the energy source
ONLY if your amp can pull a 2 ohm load! Which is vary few but your more expensive amp can pull 1/2 ohm load
The hook load capacity is the maximum weight that a drilling rig can lift. The drilling depth is how deep the rig can drill into the ground. The hook load capacity needs to be sufficient to lift the drill string and other equipment needed to reach the desired drilling depth without exceeding the rig's lifting capacity.
The load is essentially what consumes electrons. For example a load on a light circuit would be a bulb. Therefore, if you don't hook up a load you aren't doing anything. It is like turning on a light switch without a bulb. It may give you some minor exercise, but it doesn't do anything useful.
poor regulation
drop
You'll see a voltage drop across a resistor if current is flowing through it. It only has to be a part of a complete circuit, i.e. one in which current is flowing.
emf and voltageAnswerElectromotive force is the potential difference created by a source, such as a battery or generator, when it is not connected to a load -in other words, on 'open circuit'.Voltage drop is the potential difference across a load, such as a resistor, which causes current to flow through that load.A voltage drop occurs, internally, in batteries and generators, when they are supplying a load. The battery or generator's terminal voltage, when supplying a load, is its e.m.f. less its internal voltage drop.
As the load current increases the losses in the circuit increases (I2R loss) and speed of the generator decreases so the voltage falls a little. and this voltage fall can be adjusted by increasing the speed of the generator and Iron losses are taken as constant losses.