Around 80 m tower height + 40m radius
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
Electricity is nearly always sold in kilowatt-hours (kW h). It is important to note that this is not a measure of kilowatts per hour (kW/h) but the product of kilowatts and hours. 1500 watts is 1.5 kilowatts. Assuming a month containing 31 days, with 24 hours per day the month would contain 744 hours. The heater uses 1.5 kW when operating, so multiplying the two gives the result that your heater is using 1116 kW h per month if it is left running all the time. Without knowing the price of a kW h in Chigaco I cannot answer further. However in Maine I pay on average about $0.16 per kW h in my market. So for me to run your heater non stop for a month it would cost me $178.56. To find this result for yourself, determine how much you pay per kW h and multiply that number by 1116 kW h.
KVA=KW*Power factor, considering PF 0.9, 6KVA=KW*0.9 KW=6/.9=6.67
20 kw
Kw can be calculated from volts be using the formula p=(voltage)square/resistance*1000
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
dont kw
The cost of a 1500 kW PV system can vary widely depending on factors such as location, quality of equipment, and installation costs. On average, a 1500 kW system can cost between $2 million to $3 million. It is recommended to obtain quotes from solar providers in your area to get a more accurate estimate.
1 kw = 1000 watt 1.5 kw = 1.5 x 1000 watt = 1500 watts
Approximately 1000-1500 kW is needed to generate 1 ton of steam depending on the efficiency of the boiler and the type of fuel used.
Answer1 kW is 3,413 BTUs. Therefore, 1500 Watts = 1.5 kW and 1.5 kW x 3413 BTU/kW = 3 413 * 1.5 = 5 119.5 BTUs per hr for a 1500 Watt heaterwhat is the electric cost/
The power of the engine and the maximum speed of the 1965 Ford Cortina 1500 GT are 78 bhp (58 kW) and 107 mph respectively.
80 bhp (81 PS/60 kW) at 57700 rpm is the power of the BMW 1500 1964 engine and its maximum speed is 150 km/h (93 mph).
Well it depends on the power efficient of each solar panel and how much light they get. If you got panels that, in normal sunlight put out 100 watts; then for 1,500,000 watts you would need: 15 thousand panels. Now lets say you use two mirrors on each panel; then you would have about three times the light/power in normal light, so 1,500,000 divided by 300: so you would need 5000 panels and 10,000 mirrors.
1TR = 3.5 KW 1TR = 3.5 KW
Electricity is nearly always sold in kilowatt-hours (kW h). It is important to note that this is not a measure of kilowatts per hour (kW/h) but the product of kilowatts and hours. 1500 watts is 1.5 kilowatts. Assuming a month containing 31 days, with 24 hours per day the month would contain 744 hours. The heater uses 1.5 kW when operating, so multiplying the two gives the result that your heater is using 1116 kW h per month if it is left running all the time. Without knowing the price of a kW h in Chigaco I cannot answer further. However in Maine I pay on average about $0.16 per kW h in my market. So for me to run your heater non stop for a month it would cost me $178.56. To find this result for yourself, determine how much you pay per kW h and multiply that number by 1116 kW h.
1,000 w = 1.000 kw 100 w = 0.100 kw 90 w = 0.090 kw