It depends on the resistance of everything connected between the terminals of the power supply.
If the resistance is infinite or very high, there is little or no current. As the resistance becomes less,
the current becomes greater.
In general, the current through a circuit with 90 volts applied to it is [ 90 / R ],
where 'R' is the resistance of everything across the 90-volt power supply.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
E/R=I. 100/50=2 amps.
A circuit with a 2 ohm resistor and a 4 ohm resistor in series with a 12 volt battery will have 2 amps flowing through each resistor. The current is the same in each resistor because they are in series, and a series circuit has constant current throughout.
polarity is of major importance in dicect current circuits. <<>> When using meters please remember that a volt meter does not connect into a circuit, the leads are placed across the component that you are measuring. It is an amp meter that connects into the circuit, becoming part of the circuit, to measure the current flowing through that circuit.
33 ohms
If a 1.5 volt battery is replaced by a 9 volt battery in a circuit, the current flowing through the circuit will likely increase. This is because the higher voltage of the 9 volt battery will provide more electromotive force, pushing more current through the circuit, assuming the resistance remains the same.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
3 Ampere
by a volt meter / ameter
Using Ohm's Law (I = V/R), the current flowing through the circuit would be 3 amperes (90V / 30Ω = 3A).
yes
480 volts and 60ohm impedence current = volt/impedence current=480/60 current=8ampeares
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
To calculate the current running through the 60 ohm resistor in a parallel circuit, you first need to find the total resistance of the circuit. For a parallel circuit, the reciprocal of the total resistance (1/RT) is equal to the sum of the reciprocals of the individual resistances (1/R1 + 1/R2 + 1/R3). Once you find the total resistance, you can use Ohm's Law (I = V/R) to calculate the current running through the 60 ohm resistor.
E/R=I. 100/50=2 amps.
2 amps
Resistance = (voltage across the circuit) divided by (current through the circuit) =12 / (3 x 10-3) = 4 KΩ