It depends on the insulation provided in winding, motor can safely run on full load current. and over that it may burn but depends on cooling system of the motor. Motor can burn if insulation fails, failure of insulation depends on only the temperature rise.
How do you calculate voltage drop for starting motor current
A series-wound commutator motor has the best starting torque because the torque is proportional to the square of the current, and the starting current is set by a current-limiting resistor which is switched out as the motor builds up speed.
Inserting resistance in series with the motor armature when starting a DC motor is necessary to limit the inrush current. At startup, the motor has low back electromotive force (EMF) due to its initial stationary state, leading to a potentially very high current that could damage the motor windings or the power supply. The resistance helps to gradually increase the current as the motor accelerates, allowing it to reach its operational speed safely. Once the motor is up to speed, the resistance can be removed or reduced to improve efficiency.
depending on kva class of the motor between 4-8 times the running current
Across the line starting of a motor can be as high as 300% of the full load amps.
How do you calculate voltage drop for starting motor current
Motor starting current is typically 5-7 times the rated current of the motor. (For three phase induction motors)
what is the starting current of 2ton window ac voltas
The starting current is high because when the motor is not rotating no back-emf is generated, leaving the starting current to be determined by the armature resistance, which should be low.
A series-wound commutator motor has the best starting torque because the torque is proportional to the square of the current, and the starting current is set by a current-limiting resistor which is switched out as the motor builds up speed.
Assuming the Motor is IE1 Efficiency and 4 Poles, the in rush current will be 1183 A
because of starting current of induction motor is very high and it damages the insulation of motor
Inserting resistance in series with the motor armature when starting a DC motor is necessary to limit the inrush current. At startup, the motor has low back electromotive force (EMF) due to its initial stationary state, leading to a potentially very high current that could damage the motor windings or the power supply. The resistance helps to gradually increase the current as the motor accelerates, allowing it to reach its operational speed safely. Once the motor is up to speed, the resistance can be removed or reduced to improve efficiency.
While starting a motor from standstill to its rated speed, the motor has to overcome the inertia and generate enough torque to over come it. In the process the motor takes higher current during the starting. Once started and set in motion the current reduces ti its normal value. Full load current is lower than the starting current normally.
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
starting current of 3 phase 75 KW induction motor
depending on kva class of the motor between 4-8 times the running current