I=vnqA
If what you're asking refers to the average speed at which a charged particle, such as an electron, travels down a conductor when a voltage is applied you can use the formula above, where I is the current, v is the average velocity of the charged particle, n is the number of those particles per square metre of the conductor, q is the charge of the particle and A is the cross-sectional area of the conductor.
Of course I=V/R
Where V is the voltage and R is the resistance of the circuit.
So a direct relationship would look like
V/R=vnqA
V=RvnqA
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Your question is unclear. But, if you are asking what the relationship between voltage and the distance between conductors is, then the higher the voltage, the greater the distance must be.
Ohm's law gives the relationship between current, voltage, and resistance. The law states that I=V/R, where I is current, V is voltage, and R is resistance. Source: university digital fundamentals
The term, 'negative voltage', refers to its direction and has nothing to do with 'negative' in the 'charge' sense. It's used to indicate the direction in which a voltage is acting in relation to another voltage ('positive' if acting in the samedirection; 'negative' if acting in the opposite direction). So your question is confusing: 'negative' in relation to what?
RMS voltage is the DC equivalent of your AC waveform. Vrms=(Vpeak)/(root two) If your peak voltage is 170V then the RMS voltage would be approx. 120 V (see related link)
voltage: it is the potentail difference between two wires. or it is the amount of energy used to force the electrons.current: it is the flow of free electrons.by Balaji,NITCAnswerThere is no such expression as 'potential voltage'. 'Voltage' is simply another word for 'potential difference'.