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To calculate the resistance of the windings on a 2.2 kW, 240 V motor, you first need to determine the current it draws. Using the formula ( P = V \times I ), the current ( I ) can be calculated as ( I = P / V = 2200 \text{ W} / 240 \text{ V} \approx 9.17 \text{ A} ). Assuming the motor operates at full efficiency, you can use Ohm's law ( R = V / I ) to find the resistance: ( R = 240 \text{ V} / 9.17 \text{ A} \approx 26.2 , \Omega ). Thus, the resistance of the windings is approximately 26.2 ohms.
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Why does a 120V-240V dual voltage single phase table saw motor produce 4 times more torque at 240V than at 120V?
I believe it has to do with the windings in the motor. When wired to 120V, half the motor has a positive polarity and the other half has a negative polarity. Then as the current alternates (60 hertz AC) the polarity flips, the magnetic poles oppose each other and cause the motor to spin. I think in a 240v winding the motor is in quadrants instead of halves. So it would be like have 4 magnets opposing each other instead of two and you have double the voltage. The calculation for electrical power (which is converted to torque) is voltage-squared divided by the resistance. If the voltage is doubled, the power is increase by 2-squared, or quadrupled. In reality, the torque produced will be slightly less than 4 times more (because some of the power is lost as heat), but it should be pretty close. -- The second answer is the best answer. The first answer could suggest several things, depending on how you read it. Nonetheless, they are all incorrect. The power calculation (in Watts) is really all you need to do. Voltage squared, divided by resistance. Resistance stays the same, so power quadruples when voltage doubles. If the motor spins at the same speed, then torque should effectively be linear with power, aside from the extra heat created in the components from the higher current.
What causes a diode to fail on a 240v solenoid valve?
Why would it? And is this the diode across the windings of the coil that supplies the back EMF (inductive kick) supression? There isn't a good reason for it to fail. A bit more information is needed here.
What is the value of resistance ot coil having impedance of 50ohm connected across 240v at 0.8 p.f?
To find the resistance of a coil with an impedance of 50 ohms connected across 240V at a power factor of 0.8, we can use the formula for power factor: ( \text{p.f.} = \frac{R}{Z} ), where ( R ) is the resistance and ( Z ) is the impedance. Rearranging gives ( R = \text{p.f.} \times Z ). Thus, ( R = 0.8 \times 50 , \text{ohms} = 40 , \text{ohms} ). Therefore, the resistance of the coil is 40 ohms.
What size run and start capacitors do you need for a WEG brand 184T 5hp 1ph 240V motor?
For a WEG brand 184T 5hp 1-phase 240V motor, you typically need a start capacitor in the range of 100-200 µF and a run capacitor around 20-50 µF. The specific values can vary based on the motor's design and application, so it's essential to check the motor's nameplate or consult the manufacturer's documentation for precise specifications. Always ensure that the voltage rating of the capacitors meets or exceeds the motor's operating voltage.
Can a 230 460 volt 3 phase motor be connected to a 277 480 volt 3 phase circuit?
Yes, that's possible, but only for low-powered motor. You know that in order to start, the stator must be supplied with voltages that are shows shift phase between them, so the trick is to use a capacitor (since it shifts phase current) to simulate a 3-phase source. As indicated in the following picture: http://freecircuitdiagram.com/wp-content/uploads/2010/10/Enabling-3-Phase-Motor-Operates-with-Single-Phase-Supply.gif
The electrical resistance of a 100w 240v bulb will be?
42 ohm
Why does a 120V-240V dual voltage single phase table saw motor produce 4 times more torque at 240V than at 120V?
I believe it has to do with the windings in the motor. When wired to 120V, half the motor has a positive polarity and the other half has a negative polarity. Then as the current alternates (60 hertz AC) the polarity flips, the magnetic poles oppose each other and cause the motor to spin. I think in a 240v winding the motor is in quadrants instead of halves. So it would be like have 4 magnets opposing each other instead of two and you have double the voltage. The calculation for electrical power (which is converted to torque) is voltage-squared divided by the resistance. If the voltage is doubled, the power is increase by 2-squared, or quadrupled. In reality, the torque produced will be slightly less than 4 times more (because some of the power is lost as heat), but it should be pretty close. -- The second answer is the best answer. The first answer could suggest several things, depending on how you read it. Nonetheless, they are all incorrect. The power calculation (in Watts) is really all you need to do. Voltage squared, divided by resistance. Resistance stays the same, so power quadruples when voltage doubles. If the motor spins at the same speed, then torque should effectively be linear with power, aside from the extra heat created in the components from the higher current.
What current will a 100w electric fan motor draw when you plug it into a 240v wall socket?
To calculate the current drawn by the 100W electric fan motor when plugged into a 240V socket, you can use the formula: Current (A) = Power (W) / Voltage (V). Therefore, Current = 100W / 240V = 0.42 Amperes. So, the motor will draw approximately 0.42A of current.
Can the resistance of a light bulb permanently change after it had been used for years?
240v is equal to how many amps
WIll sump motor blow if I connect 240V?
It may not blow, but it will turn twice as fast and burn out very quickly. It is meant for 110 only. Check the sump pump. Some of them can be wired either 120v or 240v. If yours is like that, just wire the motor for 240v and plug it in.
What is the amount of current that flows through an electrical pathway with a resistance of 48 and voltage of 240v?
5amps of current will flow it
What would cause a 240V motor to surge?
Your air compressor drive belt is loose, Tighten it up! geterdone
What causes a diode to fail on a 240v solenoid valve?
Why would it? And is this the diode across the windings of the coil that supplies the back EMF (inductive kick) supression? There isn't a good reason for it to fail. A bit more information is needed here.
How do you rewire a 120V or 240V motor running on 120V volts back to 240V?
I'm assume you're not working on a polyphasic system, so you have 2 hots and one neutral with 220VAC across the hots and 120VAC across either hot and neutral: The motor should have two sets of windings inside. The leads for these windings should be behind a cover plate or in a junction box. Since the motor is currently wired for 115V, the windings should be in parallel. Write down which wires are connected to what. This is very important in case you make a mistake! A good way to think about this is you have four wires, numbered 1 - 4. Winding one has two leads, 1 and 2. Winding 2 has two leads, 3 and 4. Right now 1 and 3 are connected to the hot, and 2 and 4 are connected to the neutral. To wire the motor in series you want 1 connected to hot1, 2 connected to 3, and 4 connected to hot2. -EDIT- There was a mistake in my first revision. The method wouldn't work for 110-220 conversion as a mistake could burn up a winding. -TJNII First, figure out which wires are winding pairs. This is very important as if you try to rewire it blind, you could burn a winding out. After writing down which wires were connected where, disconnect all junctions. Connect your multimeter (on resistance) to one of the wires you disconnected from the hot. Find out which wire from the neutral is paired with it. The matching lead will have a fairly low resistance. You know know which leads are 1 - 4. Wires 1 and 2 are the pair you just found, and wires 3 - 4 are the pair you didn't need to test. Wires 1 and 2 connected to the hot, and wires 3 and 4 connected to the neutral. Connect 1 to hot1, 2 to 3, and 4 to hot2. Check the resistance across 1 and 4. If it is not about double the restance you found in the above step, you made a mistake. Re-check your wiring. The motor should now run. If the motor tries to turn but cannot, or turns slowly while humming very loudly, wires 1 and 2 are reversed. Do not run the motor with the windings in parallel, or run a single winding off 220V! You will burn it out! <<>> The linked site has just about any connection you might need. See related links below.
What is the advantage of a Star Delta Motor Starter?
The inrush current to the starting motor is lower due to the the motor coils being in series across the line creating a higher impeadence. When the starter connects to delta connection the motor is already turning and it does not have to go through the locked rotor phase. This system is being phased out now with the use of electronic soft starts and by-pass contactors.To start a motor direct on line (DOL) in delta requires approximately 6 to 8 times the full load current of the motor and delivers full torque. Delta places 415v across each of the windings on the motor. A Star-Delta starter starts the motor in Star which places 240v across each winding on the motor. This results in a lower starting current and also a lower starting torque.
What is the value of resistance ot coil having impedance of 50ohm connected across 240v at 0.8 p.f?
To find the resistance of a coil with an impedance of 50 ohms connected across 240V at a power factor of 0.8, we can use the formula for power factor: ( \text{p.f.} = \frac{R}{Z} ), where ( R ) is the resistance and ( Z ) is the impedance. Rearranging gives ( R = \text{p.f.} \times Z ). Thus, ( R = 0.8 \times 50 , \text{ohms} = 40 , \text{ohms} ). Therefore, the resistance of the coil is 40 ohms.
What is the current drawn by the motor if it is connected to a 240V supply?
The motor might be a big one or a small one. A small one takes a little current, a big one takes a big current.
