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A 20 ohm a 60 ohm a 80 ohm resistor are connected in parallel to a 110 volt power source what is the total current flowing in the circuit?
The total current flowing in the three resistors, i = 110 V / r(eq); where r(eq) is the equivalent resistance of the three parallel resistors. r(eq) = 1/[(1/20) + (1/60) + (1/80)] = 1 / 0.079 ohms = 12.63 ohms. i = 110 V / 12.63 ohms = 8.71 amps.
How do you find unknown value of a resistor when total resistor values and voltage are known in a series circuit?
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
When a 10 ohm resistor is connected in parallel to a 15 ohm resistor what percentage of the total current will flow through the 10 ohm resistor?
There will be 20 amps flowing through the 5 ohm resistor. We could do some math and all to figure voltage drops and some other things, but let's cut to the chase and see what's happening. Based on what we know about series circuits and about parallel circuits, we can shred this in nothing flat. So let's. First, we're told 30 amps flows in the circuit. That's the total current, and it will be the current through the first 10 ohm resistor. It has to be. The the 30 amps "splits" to flow through the parallel network of the 10 ohm and 5 ohm resistors. That's 30 amps that has to "split" and some will go through the 10 ohm resistor and some will go through the 5 ohm resistor. With me? Sure. Now for the "trick" here. Since the 5 ohm resistor has only half the resistance of the 10 ohm resistor, twice as much current will flow through it as the 10 ohm resistor. Make sense? Yup. Let's finish this. Since there is twice as much current flowing in the 5 ohm resistor 'cause it's got half the resistance of the 10 ohm resistor, if we have "x" amount of current flowing in the 10 ohm resistor, then we'll have "2x" amps of current flowing in the 5 ohm resistor. That's "3x" amps total, and the "3x" amps equals 30 amps. See through it now? There will be 10 amps flowing through the 10 ohm resistor, and 20 amps flowing through the 5 ohm resistor. Piece of cake.
When you add a resistor to a series circuit what will happen to the total current?
increase.
What are the relations between individual voltages and the total voltages when resistors are connected in series and in parallel?
-- The current in each individual resistor is (voltage across the whole circuit) divided by (the resistance of the individual resistor). -- The current in any individual resistor is less than the total current in the circuit. -- The total current in the circuit is the sum of the currents through each individual resistor.
What is the total current flowing through a 45 ohm resistor (1.4 amps) and a 20 ohm resistor (1.8 amps)?
Just add the amps (3.2 amps).
What happens to the ammeter reading if resistor is removed?
If the resistor is removed from the circuit, the total resistance in the circuit decreases. This causes the total current in the circuit to increase, which would result in an increase in the ammeter reading.
What happens in a series circuit if one of the resistors is replaced with a resistor having a lower resistance value?
In a series circuit, if one resistor is replaced with a resistor of lower resistance, the total resistance in the circuit decreases. This leads to an increase in the overall current flowing through the circuit.
A 120 ohm resisto a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source What is the current running through the 60 ohm resistor?
If they're in parallel, then each resistor acts as if it were the only one,and the presence of any others is irrelevant.The current through the 60-ohm resistor is I = E/R = (120/60) = 2 amperes.
A 120 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source what is the current running through the 40ohm resitor?
The current through the 40-ohm resistor is ( E / R ) = (120 / 40) = 3 amperes.The current through the 40-ohm resistor doesn't depend on the 120-ohm resistor. It's the samewhether the 120-ohm is there or not. It would also be the same if there were any other resistor,with any other resistance, connected in place of the 120-ohm resistor. It would also be the sameif there were 3,000 more resistors in parallel, with all different values of resistance (as long asthe whole conglomeration didn't exceed the capabilities of the power source).
A 5 ohm resistor a 10 ohm resistor and a 15 ohm resistor are connected in series to a 120 volt power source What is the amount of current flowing between the 5 ohm resistor and the 10 ohm resistor?
3.0 or threeAnswerIt depends how they are connected.In series, ther total resistance will be 220 ohms and, so, the current will be 120/220 = 0.545 A.In parallel, ther total resistance will be 20 ohms and, so, the current will be 120/20 = 6 A.
A 120 resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source what is the current running though the 40 ohm resistor?
To calculate the total current in the circuit, you first need to find the total resistance by using the formula for resistors in parallel: 1/Total Resistance = 1/120 + 1/60 + 1/40. Once you have the total resistance, you can use Ohm's Law: Current = Voltage / Total Resistance. Finally, to find the current running through the 40 ohm resistor, you divide the total current by the resistance of the 40 ohm resistor.
An electric dc circuit is attached to a 12 volt battery and has a 3ohm resistor in it What is the current flowing through the circuit?
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.
You are just asking that let us assume you have connected 2 or 3 resistors in a circuit and the current flowing through the circuit and from all the resistors will be same but how?
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
Five series resistors each dissipate 50 mW of power What is the total power?
AS:total power = P1 + P2 + P3 + .......so,total power = 5(50mW)= 0.25Wtotal power dissipated by the five resistors is 0.25W.
A 20 ohm a 60 ohm a 80 ohm resistor are connected in parallel to a 110 volt power source what is the total current flowing in the circuit?
The total current flowing in the three resistors, i = 110 V / r(eq); where r(eq) is the equivalent resistance of the three parallel resistors. r(eq) = 1/[(1/20) + (1/60) + (1/80)] = 1 / 0.079 ohms = 12.63 ohms. i = 110 V / 12.63 ohms = 8.71 amps.
A 120 ohm resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source. What is the current running through the entire circuit?
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