It depends. In some cases it may destroy some components. Depends on application and rating of components in use.
It works normally. Well actually there are 380 volts across two lines of a 3 phase AC source, so it should work normally.
To find the resistance that produces a current of 8 amps when connected to 24 volts, you can use Ohm's Law, which states that ( V = I \times R ). Rearranging the formula to solve for resistance gives ( R = \frac{V}{I} ). Substituting the values, ( R = \frac{24 \text{ volts}}{8 \text{ amps}} = 3 \text{ ohms} ). Thus, a resistance of 3 ohms will produce a current of 8 amps when connected to 24 volts.
No, you will not obtain 230 volts. From a wye connected three phase 480 volt supply, 277 volts can be obtained from one phase leg and the neutral on the wye connection. 480 volts/1.73 (sq. root of 3) = 277 volts.
Your description of the system is either contradictory or incomplete, therefor no answer can be given.
3 Kv = 3,000 volts.
Because they are connected in series. Lets say you have a flashlight that holds 2 D cell batteries. Each battery puts out 1.5 volts. Connect them in series and together they put out 3 volts. The flashlight is designed to run on 3 volts. A electronic device that uses 4 AA batteries is using 6 volts even though each battery is only putting out 1.5 volts. Connected in series you add to the voltage with the addition of each new battery.
4.5 volts in series; 1.5 volts in parallel.
It works normally. Well actually there are 380 volts across two lines of a 3 phase AC source, so it should work normally.
No. Your power supply must be able to supply rated voltage (12 volts) and rated current (3 amps).
When three 1.5-volt batteries are connected in series, they will provide a total voltage of 4.5 volts to the LED. If the LED's forward voltage rating is lower than 4.5 volts (typically around 2-3 volts for standard LEDs), it will illuminate brightly. However, if the voltage exceeds the LED's rating, it could lead to overheating and damage the LED. To ensure safe operation, a current-limiting resistor is often used in series with the LED.
To find the resistance that produces a current of 8 amps when connected to 24 volts, you can use Ohm's Law, which states that ( V = I \times R ). Rearranging the formula to solve for resistance gives ( R = \frac{V}{I} ). Substituting the values, ( R = \frac{24 \text{ volts}}{8 \text{ amps}} = 3 \text{ ohms} ). Thus, a resistance of 3 ohms will produce a current of 8 amps when connected to 24 volts.
Unlikely. 3 volts in stead of 4.5 volts is a too big gap between that it gets and what it expects.
9/3 = 3 volts per millimeter = 3,000 volts per meter.
No, you will not obtain 230 volts. From a wye connected three phase 480 volt supply, 277 volts can be obtained from one phase leg and the neutral on the wye connection. 480 volts/1.73 (sq. root of 3) = 277 volts.
According to me the information about the 3 Volts DC batteries is incomplete i.e.The amp-hr capacity is not provided.If this is known then the answer would be 3X the amp-hr .
difference is 2.7 amperes in numbers will be 12 volts 3 amps and the other will be 12 volts .3 amps
The voltmeter would read 12 volts. An ammeter connected to to battery would only read 4 amps (12 volts divided by 3 ohms =4)