If the wire length is 100m and the Diameter is 1mm calculate the Resistance of wire?
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
we have this 1/Re = (1/R1)+(1/R2) for calculating the effective resistance when resistances are connected in parallel so the answer would be Re =( 70*30) / (70+ 30) = 21 ohms
10.2 kilo ohms is the resistance necessary for 1 volt to induce a current of 98.04 micro amperes. Ohm's law: voltage equals current times resistance.
The combined resistance will be 2 Ohms.
The conductance of a wire is the reciprocal of its resistance. Therefore, for a wire with a resistance of 400 ohms, the conductance would be 1/400 siemens, or 0.0025 siemens.
If the diameter of the circular wire is doubled, the resistance will decrease by a factor of four, resulting in a resistance of 0.25 ohms. Resistance is inversely proportional to the cross-sectional area of the wire, which is affected by the diameter.
The conductance of a wire can be calculated by taking the reciprocal of its resistance. In this case, the conductance would be 1/400 ohms^-1, or 0.0025 Siemens.
The resistance value of a 1 meter copper wire depends on its gauge (thickness) and temperature. For example, a 1 meter wire of 24-gauge copper has a resistance of about 25.67 ohms at room temperature. It is important to consider these factors when calculating the resistance of copper wire.
If the wire length is 100m and the Diameter is 1mm calculate the Resistance of wire?
Lets say the resistance of copper wire is 1 ohm per meter and the wire is 10 meters long then resistance of wire is 10 ohms* If we then theoretically take the resistance of the wire at 10 ohm* and the voltage from the source at 10V then the current would be* I=V/R 10/10 or 1A If we shorten the wire to 9m then resistance of wire is 9 ohms so current if V does not change would be I=V/R 10/9 or 1.111111111111111111111A *This is without loss or other factors
Trick question. From Ohms law resistance equals voltage over current (R=V/A). To get 1 ampere at 1 volt the resistance must be 1 ohm!
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
In a parallel circuit, the total resistance is calculated as the reciprocal of the sum of the reciprocals of each individual resistance. So, for three resistances of 20 ohms, 20 ohms, and 10 ohms, the total resistance will be 1 / (1/20 + 1/20 + 1/10) = 1 / (0.05 + 0.05 + 0.1) = 1 / 0.2 = 5 ohms.
The voltage drop must be less than 5%, which is 11 volts. Thus the total resistance must equal 11/50 ohms or less, that is 11 volts divided by 50 amps. For a two-wire line the total wire length is 700 feet so the required resistance per foot is 11/(50*700) ohms per foot, or 0.000314 ohms per foot, equal to 0.001 ohms per metre for a single wire. A wire of 1 sq. mm. cross section has a resistance of 0.0168 ohms per metre, we need .001 ohms per metre, therefore the wire needs a cross section of more than 16.8 mm sq. In the USA that means the necessary wire size is 5 AWG.
Assuming the allowed volt drop is 5% or 5.5 volts, the wire resistance has to be 5.5/15 ohms or less, 0.367 ohms. The total length of wire is 600 metres so the resistance per metre is 0.00061 ohms. 1 sq-mm copper wire has a resistance of 0.0168 ohms/metre so you need wire with a size of 0.0168/0.00061 sq-mm, or 27.5 sq-mm. The next size up is 35 sq-mm in European cable size, or #2 AWG in America.