The conductance of a wire is the reciprocal of its resistance. Therefore, for a wire with a resistance of 400 ohms, the conductance would be 1/400 siemens, or 0.0025 siemens.
The conductance of a wire can be calculated by taking the reciprocal of its resistance. In this case, the conductance would be 1/400 ohms^-1, or 0.0025 Siemens.
Use Ohm's Law - in this case, solving for current: I = V/R (current = voltage divided by resistance). Since you are using standard SI units, the answer will be in amperes.
The amount of heat something can dissipate into the air depends greatly on the size of it's surface area. This is why the thinner filament will burn more than the thicker part, because the thin part can not dissipate the heat as quickly. Filaments are in the past, get LED bulbs.
The current flowing through a 100-ohm resistor connected to a 0.40-volt source can be calculated using Ohm's Law, which states that current (I) = voltage (V) / resistance (R). In this case, I = 0.40V / 100Ω = 0.004 amperes, or 4 milliamperes of current.
To calculate the acceleration of the fall with air resistance, we need to consider the net force acting on the object. The net force is the difference between the force of gravity (weight) and the force of air resistance. Given that the weight of the object is 50 kg * 9.8 m/s^2 = 490 N, and the air resistance is 400 N, the net force is 490 N - 400 N = 90 N. Using Newton's second law (F = ma), the acceleration can be calculated as 90 N / 50 kg = 1.8 m/s^2.
The conductance of a wire can be calculated by taking the reciprocal of its resistance. In this case, the conductance would be 1/400 ohms^-1, or 0.0025 Siemens.
25 ohmsAnswerResistance is measured in ohms. Conductance is measured in siemens. Conductance is the reciprocal of resistance. So the ohmic equivalent of 400 siemens is 2.5 milliohms.
400 ohms
To find the resistance needed in series with the 250 ohms inductive reactance to give a total impedance of 400 ohms, we use the Pythagorean theorem for the impedance triangle in series circuits. Given the inductive reactance (X) = 250 ohms, total impedance (Z) = 400 ohms, and resistance (R) = unknown, we have R² + X² = Z². Substituting the values, we get R = √(Z² - X²) = √(400² - 250²) = √(160000 - 62500) = √97500 ≈ 312.5 ohms. Therefore, approximately 312.5 ohms of resistance should be connected in series with the 250 ohms inductive reactance to achieve a total circuit impedance of 400 ohms.
The formula you are looking for is, R = Volts (squared)/Watts.
I believe the symbol you used, the "omega" stands for ohms, a measure of resistance in electricity and electrical work.
The resistance for 400 ft. of 10 AWG copper is .4 ohms. This would be a voltage drop of (.4 x 20) or 8 volts. For 120 VAC service this is a 6% which is a bit high. At 240 volts it is 3%. At 8 AWG the resistance is .251 ohms which will give you better performance.
Line current = 10MW / 500kV = 20A Assuming the 1000 ohms is the resistance of the entire transmission line, end to end. Power loss = line current ^ 2 * line resistance = 20A ^ 2 * 1000 ohms = 400 KW
The resistance depends on how big the motor is. A small motor (less then 2-3 kW) , have greater resistance than a bigger one. Typically small motors have from 10 - 20 ohms to a few ohm. A 13 kWatt motor have typically 1-2 Ohm. A big 400 KWatt's motor have typically 10 milli ohms between the phases.
Which of what following? The inductance of the coil must be higher than the resistance of the coil, since the supply is providing 200*10 = 2000VA. 2000VA =sqrt[ (I^2 * R)^2 + (I^2 * L)^2] 4000000VA = I^4*R^2 + I^4*L^2 400 = R^2 + L^2 and 1000Watts = R*I^2, so R = 10 ohms 400 = 100 + L^2 L = 17.3 ohms
I also have a '72 beetle - with a busted fuel sender unit. I have the installed one and another older one. They both have a floater attached to an arm that makes contact with resistance wire on the inside of the unit. The resistance wire is wrapped on the inside. So the resistance (and thus the voltage reading) changes as the contact (floater) moves. It seems that the delicate resistance wire is the weak point in the design and usually breaks. The contact part that brushes over the wire also sometimes can be a bit bent. If you can see the wire is broken you can try to replace the whole winding by removing the old and determining the value (in ohms/meter) and buying new resistance wire and rewinding it. Alternatively try and replace the whole resistance wire setup with a potentiometer (variable resistor) - I think that probably better. I actually got the old unit I had working this evening just to blow it up when I was clever enough to 'test' it with 12V without adding a current limiting resistor. before blowing it up I measured the resistance range: 0-400 ohms. the windings are regularly spaced, so the resistance should rise linearly with movement of the floater. I see if i can get anything fixed and let you know. Otherwise, if you live in USA try wolfsburgwest.com in Cali. they have new ones for $33. I live in South Africa :( - so I'll probably have to try and fix it or pay like more than double that.....
Eureka wire, also known as constantan wire, is commonly used in the construction of resistance wires for electrical components like heating elements and resistors. It has a stable resistance over a wide range of temperatures, making it ideal for applications where consistent electrical properties are required.