The conductance of a wire is the reciprocal of its resistance. Therefore, for a wire with a resistance of 400 ohms, the conductance would be 1/400 siemens, or 0.0025 siemens.
The conductance of a wire can be calculated by taking the reciprocal of its resistance. In this case, the conductance would be 1/400 ohms^-1, or 0.0025 Siemens.
Use Ohm's Law - in this case, solving for current: I = V/R (current = voltage divided by resistance). Since you are using standard SI units, the answer will be in amperes.
The amount of heat something can dissipate into the air depends greatly on the size of it's surface area. This is why the thinner filament will burn more than the thicker part, because the thin part can not dissipate the heat as quickly. Filaments are in the past, get LED bulbs.
The current flowing through a 100-ohm resistor connected to a 0.40-volt source can be calculated using Ohm's Law, which states that current (I) = voltage (V) / resistance (R). In this case, I = 0.40V / 100Ω = 0.004 amperes, or 4 milliamperes of current.
To calculate the acceleration of the fall with air resistance, we need to consider the net force acting on the object. The net force is the difference between the force of gravity (weight) and the force of air resistance. Given that the weight of the object is 50 kg * 9.8 m/s^2 = 490 N, and the air resistance is 400 N, the net force is 490 N - 400 N = 90 N. Using Newton's second law (F = ma), the acceleration can be calculated as 90 N / 50 kg = 1.8 m/s^2.
The conductance of a wire can be calculated by taking the reciprocal of its resistance. In this case, the conductance would be 1/400 ohms^-1, or 0.0025 Siemens.
25 ohmsAnswerResistance is measured in ohms. Conductance is measured in siemens. Conductance is the reciprocal of resistance. So the ohmic equivalent of 400 siemens is 2.5 milliohms.
400 ohms
To find the resistance needed in series with the 250 ohms inductive reactance to give a total impedance of 400 ohms, we use the Pythagorean theorem for the impedance triangle in series circuits. Given the inductive reactance (X) = 250 ohms, total impedance (Z) = 400 ohms, and resistance (R) = unknown, we have R² + X² = Z². Substituting the values, we get R = √(Z² - X²) = √(400² - 250²) = √(160000 - 62500) = √97500 ≈ 312.5 ohms. Therefore, approximately 312.5 ohms of resistance should be connected in series with the 250 ohms inductive reactance to achieve a total circuit impedance of 400 ohms.
If the ohm meter reads 40 ohms on the resistance x 10 range, the actual resistance value is 40 ohms multiplied by 10. Therefore, the resistance is 400 ohms.
The formula you are looking for is, R = Volts (squared)/Watts.
To find the resistance of a 100W bulb operating at 200V, you can use the formula ( R = \frac{V^2}{P} ), where ( R ) is resistance, ( V ) is voltage, and ( P ) is power. Substituting the values, ( R = \frac{200^2}{100} = \frac{40000}{100} = 400 ) ohms. Therefore, the resistance of the 100W bulb at 200V is 400 ohms.
I believe the symbol you used, the "omega" stands for ohms, a measure of resistance in electricity and electrical work.
The resistance for 400 ft. of 10 AWG copper is .4 ohms. This would be a voltage drop of (.4 x 20) or 8 volts. For 120 VAC service this is a 6% which is a bit high. At 240 volts it is 3%. At 8 AWG the resistance is .251 ohms which will give you better performance.
The ohms value at the stator and signal coil can vary depending on the specific make and model of the engine or generator. Typically, a stator coil may have a resistance ranging from a few ohms to several hundred ohms, while a signal coil often has a lower resistance, usually between 100 to 400 ohms. It's essential to refer to the manufacturer's specifications for precise values, as they can differ significantly between different systems. Always use a multimeter to measure the resistance for accurate readings.
Line current = 10MW / 500kV = 20A Assuming the 1000 ohms is the resistance of the entire transmission line, end to end. Power loss = line current ^ 2 * line resistance = 20A ^ 2 * 1000 ohms = 400 KW
The resistance depends on how big the motor is. A small motor (less then 2-3 kW) , have greater resistance than a bigger one. Typically small motors have from 10 - 20 ohms to a few ohm. A 13 kWatt motor have typically 1-2 Ohm. A big 400 KWatt's motor have typically 10 milli ohms between the phases.