First of all the power consumed is only dependent on the load (eg. any appliance) connected to the source. A load will always draw its rated power. If you have increased your voltage to twice then the current drawn by the device will become half but the power consumed will remain same.
the power consumed is given by:
P= V*I* cos(fi)
here for a given load P(power), cos(fi) are constants.
Then if V becomes 2V then current will be I/2.
It is halved. coz voltage=current * resistance
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
A: Nothing will happen if the load increases or even removed the voltage will go to the open voltage condition no harm.
It is halved. coz voltage=current * resistance
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
If the voltage is doubled and the resistance is constant, Ohm's Law states that the current will also double. This is because the relationship between voltage, current, and resistance is linear, and increasing the voltage will directly increase the current flow.
If resistance is doubled in a circuit with constant voltage, Ohm's Law (V=IR) states that current (I) would be halved since the voltage is constant. This is because the relationship between resistance and current is inversely proportional.
In a parallel circuit, the total resistance remains the same when the voltage applied is doubled. Each branch in the parallel circuit will experience the same increase in voltage, but their individual resistances will remain constant.
double if resistance is considered same.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
it will cause a Short Circuit
by the ohms law we can clearly say that the current is the ratio of voltage to the resistance.as the resistance is doubled the current should be halved.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
If the voltage in a circuit were doubled, the current would also double according to Ohm's Law (I = V/R), assuming the resistance in the circuit remains constant. This is because current is directly proportional to voltage when resistance is held constant.
The current is doubled.I = V/RI=2V/RLets assign arbitrary numbers to voltage and resistance to evaluate what happens. Voltage will be 8 volts and resistance will be 2 ohms.I = 8/2 Therefore current = 4ampsIf voltage is doubled then,I =2(8)/2I=16/2I = 8 amps