Peak to Peak is the most positive peak to the negative peak value. Or find any peak value and multiply by 2.
Inrush current has a positive peak because it represents the initial surge of electrical current when a device, such as a motor or transformer, is first energized. This peak occurs as the system attempts to rapidly establish the magnetic field necessary for operation, resulting in a brief but substantial increase in current. The positive peak reflects the instantaneous demand for power to overcome inertia and other resistive forces, before settling down to the normal operating current once the device stabilizes.
200 volts peak-to-peak is 100 volts peak, which is 70.7 volts rms (standing for root-mean-square) also called "effective". This 70.7 volts is the DC voltage with the same heating power as the peak-to-peak. The relationship is: rms (aka RMS) equals peak-to-peak divided by 2, then divided again by square-root of 2 (1.414). The division by 2 gets us from peak-to-peak to just peak. The next division takes us to rms. If you get an AC voltrage with no description, for exmple 120 volts AC, it is RMS (effective). The USA AC standard supply voltage is 120 (also called 117) volts RMS. The USA peak is 117 x 1.414 (square root of 2) = 165 volts peak, = 330 volts peak-to-peak.
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
A: AC or our line voltage is sinusoidal in nature it goes up to a positive peak returns to zero and proceed to the negative peak. 120V AC is actually swinging from peak to peak. It is 120 volts but the peak is the 120 v times 1.41 or 169.2 volts and since it also go negative then the peak to peak 120 volts times 2.82 or 338.40 volts or twice the peak voltage
temperature
The peak wavelength, is connected to the temperature of the objects. we have short peak wavelength when the temperature is high.
The surface temperature of a star can be determined by analyzing its spectrum. Specifically, scientists can observe the peak wavelength of light emitted by the star and use Wien's Law, which relates the peak wavelength to the temperature of the emitting object. By measuring the peak wavelength, astronomers can calculate the surface temperature of the star.
Approximately 4200K. This is based on Wien's displacement law, which relates the peak wavelength of a black body radiator to its temperature.
This question has a real subtlety in it. The simplest answer is given by Wein's Law, sometimes called Wein's Displacement Law: The peak of the spectrum for any "blackbody" (this works approximately for stars and people, basically any opaque object). Wavelength of peak emission = (Stefan's constant, which you can look up) x 0.0029meter / temperature in Kelvins. According to this formula, the peak is in the green part of the spectrum. But a lot of light is given off across the visual part of the spectrum so it looks whitish to me. Here's the subtlety that few people realize. This all works only when you plot the spectrum as the emission per unit wavelength. You can also plot the emission per unit frequency. Then the peak is at a different location!
The peak wavelength calculated using Wien's displacement law is the wavelength at which the intensity of radiation emitted by a black body is highest. This peak wavelength is inversely proportional to the temperature of the black body, with higher temperatures resulting in shorter peak wavelengths.
The temperature of a glowing body determines the peak wavelength of light emitted according to Wien's Law. As temperature increases, the peak wavelength decreases, meaning hotter objects emit more blue and cooler objects emit more red light.
The star emitting the shortest wavelength of its peak frequency will be a star with high temperature, such as a blue star. This is because the wavelength of light emitted by an object is inversely proportional to its temperature according to Wien's law.
Yes. The apparent colour of a star is related to the peak wavelength of the light it emits. According to Wien's displacement law (look it up in Wikipedia) the peak wavelength is inversely proportional to the temperature. The higher the temperature, the shorter the peak wavelength. Wavelength decreases as one moves from red to blue in the visible spectrum, so a red star is cooler than a blue one.
To determine the temperature of a star, you would typically measure its spectrum and analyze the peak wavelength of the emitted light using Wien's Law. This law states that the wavelength at which the emission of a black body spectrum is maximized is inversely proportional to its temperature. Additionally, measuring the star's color index can provide insights into its temperature, as different temperatures emit different colors of light.
The peak output wavelength for an incandescent light bulb is typically in the infrared region, around 1000 nm. However, a significant portion of the emitted light is also in the visible spectrum, with peak emission in the red-yellow range.
The equation for the wavelength of maximum intensity (peak wavelength) can be calculated using Wien's Law, which is λmax = b / T, where λmax is the peak wavelength, b is a constant (2.897 x 10^-3 m*K), and T is the temperature in Kelvin.