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The breakdown voltage is greater than the barrier potential because it represents the voltage at which a significant increase in current occurs due to the breakdown of the insulating properties of a material, such as a diode or semiconductor junction. While the barrier potential is the voltage required to overcome the energy barrier for charge carriers to cross the junction, breakdown voltage indicates the point at which the electric field becomes strong enough to ionize atoms or create charge carriers, leading to a dramatic increase in conduction. Thus, the breakdown voltage must exceed the barrier potential to initiate this avalanche of charge carriers.

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How can you get the largest voltage difference?

There is no such thing as a 'voltage difference'! 'Voltage' means 'potential difference', so what you appear to be asking is "How do you get the largest potential difference difference?'! Potential difference is caused by the separation of charges between two points. The greater the amount of charge separation, the greater the potential difference.


Why does a diode not conduct until the cut in voltage is reached?

Cut in voltage is the minimum voltage required to overcome the barrier potential. In other words it is like trying to push a large boulder....it may not be possible to push a large boulder by one person but it may be done if 2 or more people try to push it together depending on the size of the boulder.....similarly....the charge carriers in the barrier region have a potential energy of about 0.6V for Silicon and about 0.2V for Germanium. so in order for the diode to conduct, it is required to overcome the potential of the charge carriers in the junction barrier region and hence only if a potential more than that of the barrier potential (cut off voltage) is applied, then electrons flow past the junction barrier and the diode conducts.


Definition of cut in voltage of diode in electronics?

zener cut in voltage


What is withstand voltage?

It is the rated test voltage that will not cause insulation breakdown.


What is the forward barrier potential of led?

Conventional LEDs are made from a variety of semiconductor materials, and radiate at different wavelengths all the way from infrared to ultraviolet. Their forward voltage drops range from about 1 volt to 6 volts, depending on the materials used. Any bias greater than the diode's forward voltage drop illuminates the device.

Related Questions

Which is greater the breakdown voltage or the barrier potential?

Breakdown voltage is far greater than barrier potential. silicon:- break-down voltage :- 5v - 450 v barrier potential ;- 0.5v to 0.7 V


Which voltage is greater in thyristor whether forward breakover or reverse breakdown voltage?

One voltage is greater in thyristor whether forward breakover or reverse breakdown voltage. The greater of the two voltages in thyristor is forward breakover voltage.


Why can't the potential barrier of a diode be used as a voltage source?

The potential barrier of a diode is caused by the movement of electrons to create holes. The electrons and holes create a potential barrier, but as this voltage will not supply current, it cannot be used as a voltage source.


Which voltage is greater in thyristor whether forward break over or reverse breakdown voltage?

It is stated that one of the voltage is greater in thyristor whether it be forward breakover or reverse breakdown voltage. It is also stated that the greater of the 2 voltages in thyristor is the forward breakover voltage.


Is fwd break over voltage is greater than reverse breakdown voltage i.e VboVbr?

forward breakover voltage is slightly smaller than reverse breakdown voltage


What is the relationship between voltage and electric potential energy difference?

Voltage is a measure of the electric potential energy difference between two points in an electric field. The greater the voltage, the greater the electric potential energy difference between the two points.


What is the typical value of the barrier potential for a germanium diode?

The typical value of the barrier potential for a germanium diode is around 0.3 to 0.4 volts. This barrier potential is the voltage required to overcome the potential barrier at the junction of the diode and allow current flow in the forward direction.


How can you get the largest voltage difference?

There is no such thing as a 'voltage difference'! 'Voltage' means 'potential difference', so what you appear to be asking is "How do you get the largest potential difference difference?'! Potential difference is caused by the separation of charges between two points. The greater the amount of charge separation, the greater the potential difference.


What resistance does a practical diode offer under reverse-biased conditions if the applied reverse voltage is greater than the breakdown voltage?

A normal diode with reverse voltage in excess of its rated breakdown voltage could fail. Resistance could be high (blown open) or low (shorted).


How can transformer oil be used in transformers with voltage rating above its breakdown voltage?

In this circumstance, the clearance between components at different potential must be increased.


Why does a diode not conduct until the cut in voltage is reached?

Cut in voltage is the minimum voltage required to overcome the barrier potential. In other words it is like trying to push a large boulder....it may not be possible to push a large boulder by one person but it may be done if 2 or more people try to push it together depending on the size of the boulder.....similarly....the charge carriers in the barrier region have a potential energy of about 0.6V for Silicon and about 0.2V for Germanium. so in order for the diode to conduct, it is required to overcome the potential of the charge carriers in the junction barrier region and hence only if a potential more than that of the barrier potential (cut off voltage) is applied, then electrons flow past the junction barrier and the diode conducts.


How does the potential barrier vanishes in the transistor?

When sufficient forward voltage is applied across the junction, the electric field opposing the further diffusion of electrons from n-type to p-type semiconductor gets lost. The electric field created due to the application of the forward voltage opposes that of the barrier potential and finally vanishes the barrier completely.