an ohmmeter contains its own power source that it uses to test the circuit. if power is still on in the circuit, at the least the meter will give incorrect readings, at the worst the meter may be damaged rendering it useless.
To determine the current in a complex circuit, you must know the total voltage supplied by the power source and the total resistance of the circuit. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current flowing through the circuit. Additionally, if the circuit is alternating current (AC), knowing the impedance is also essential.
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
A circuit can have as little as two components 1 Must have a power source 2. Something for that power source to power, for example a light *Assuming you already know you need wires to complete the circuit
Power is voltage times current. If power and voltage remains the same, then current cannot decrease - it must also remain the same.The only viable explanation, assuming the question is valid, is that there is a parallel circuit, and one resistance increases while the other decreases, keeping the net resistance the same, but shifting the power from one branch to the other.Another answerNormally, if the voltage remains the same and the current decreases in a particular circuit, then the resistance of that circuit must be increasing and the total energy input must also reduce.If the total energy input remains constant (and yet the voltage remains the same) then some of the current being supplied by the source - and therefore also some of the energy - must be going to some other place outside the circuit in question, e.g. there could now be a ground fault...
No, ammeters have a low internal resistance. This is so that when they are put in series with a circuit, they change the circuit's operating characteristics as little as possible.Contrast this with voltmeters, which do have a high internal resistance, and which are intended to be placed in parallel with the circuit they are measuring.Use the link below to the related question on why ammeters have a low internal resistance and read through that information to see why things are the way they are.
To determine the current in a complex circuit, you must know the total voltage supplied by the power source and the total resistance of the circuit. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current flowing through the circuit. Additionally, if the circuit is alternating current (AC), knowing the impedance is also essential.
The power source must be disconnected from the circuit under test before connecting an ohm meter to prevent potential damage to the meter or the circuit. This ensures that there are no active voltages present while taking resistance measurements.
To limit the power to 480 watts in a 240-volt circuit, you can use the formula ( P = \frac{V^2}{R} ), where ( P ) is power, ( V ) is voltage, and ( R ) is resistance. Rearranging the formula gives ( R = \frac{V^2}{P} ). Substituting the values, ( R = \frac{240^2}{480} = \frac{57600}{480} = 120 ) ohms. Therefore, a resistance of 120 ohms must be placed in the circuit.
If it's a pure inductor, no power consumption. However it must be wound using unobtanium wire which has zero resistance, and the core must be vacuum. Air is nearly lossless.
a meter uses its own supply to measure resistance. you dont have to remove the resistor from the circuit but you must isolate it from the circuit supply to get an accurate reading.
For a circuit to get cold, the voltage across the circuit must decrease, and the resistance within the circuit must increase. This decrease in voltage reduces the energy flowing through the circuit, while the increase in resistance limits the flow of current, resulting in less heat generation. By manipulating these two factors, the circuit can be cooled down effectively.
The sum of all the power drops in a series circuit must equal
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
A circuit can have as little as two components 1 Must have a power source 2. Something for that power source to power, for example a light *Assuming you already know you need wires to complete the circuit
An Ohmmeter.
Power is voltage times current. If power and voltage remains the same, then current cannot decrease - it must also remain the same.The only viable explanation, assuming the question is valid, is that there is a parallel circuit, and one resistance increases while the other decreases, keeping the net resistance the same, but shifting the power from one branch to the other.Another answerNormally, if the voltage remains the same and the current decreases in a particular circuit, then the resistance of that circuit must be increasing and the total energy input must also reduce.If the total energy input remains constant (and yet the voltage remains the same) then some of the current being supplied by the source - and therefore also some of the energy - must be going to some other place outside the circuit in question, e.g. there could now be a ground fault...
The three requirements for a complete circuit are a source of electrical energy (such as a battery), a conductive path (such as wires), and a load (such as a light bulb). The circuit must be closed to allow the flow of current.