The resistance in Ohm
5000 For Parallel resistors: Rtotal = R / N Rtotal is total resistance R = Value of resistors N = number of resistors 15 = 75000 / N N = 5000
The equivalent resistance, from corner to corner, of 12 resistors connected in a cube is 5/6 that of a single resistor.Proof:Start from one corner and flow current through to the opposite corner. You have three resistors. Each of those three resistors is connected to two resistors, in a crisscross pattern. Those six resistors are then connected to three resistors which are connected to the other corner. By symmetry, the voltages at the upper junctions are the same, and then same can be said for the lower junction. You can then simplify the circuit by shorting out the upper junctions and (separately) the lower junctions. This means the circuit is equivalent to three resistors in parallel, in series with six resistors in parallel, in series with three resistors in parallel. This is 1/3 R plus 1/6 R plus 1/3 R, or 5/6 R.
libolo
r=i/v
We have n identical resistors, call them R1, R2 etc up to Rn. All have resistance R. Resistance of the whole circuit = 1/(1/R1 + 1/R2 + ... + 1/Rn) = 1/(n*(1/R)) = 1/(n/R) = R/n So it's the resistance of one resistor, divided by the number of resistors.
when we want maximum resistance they are connected in series. when resistors are connected in series total resistance is maximum when resistors are connected in parallel total resistance is minimum for series total R=R1+R2+R3......... for parallel R1 in parallel to R2 total 1/R=(1/R1)+(1/R2) ie R=(R1*R2)/(R1+R2)
Two 3-ohm resistors in parallel have an effective resistance of 1.5 ohms.I = E/R = 12/1.5 = 8 AmperesNote: Use big resistors. The power dissipated by each resistor is E2/R = 48 watts !
Resistors in parallel equation is !/R = 1/r(1)_ + 1/r)2) + 1/r(3) Since they are all 8 ohms. Then 1/R = 1/8 + 1/8 + 1/8 1/R = 3/8 R = 8/3 R = 2 2/3 = 2.6666....
Measure the plate resistors' (R) voltage (E) and use Ohms law to convert that to amps (I). I=E/R
2003 Ohms. R = (R1 x R2)/( R1 + R2) Where R = 667 and R1 = 1000 then R2 = 2003
Call the total effective resistance 'R'. If the values of the individual parallel resistors are 'A', 'B', 'C', 'D' etc., then 1/R = (1/A) + (1/B) + (1/C) + (1/D) etc. Or, R = 1 divided by { (1/A) + (1/B) + (1/C) + (1/D) } The more resistors there are in parallel, the SMALLER the effective resistance becomes.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.