We have n identical resistors, call them R1, R2 etc up to Rn. All have resistance R.
Resistance of the whole circuit
= 1/(1/R1 + 1/R2 + ... + 1/Rn)
= 1/(n*(1/R))
= 1/(n/R)
= R/n
So it's the resistance of one resistor, divided by the number of resistors.
What do you mean by a 'parallel delta' circuit -is there such a connection.
The ratio of current flow through individual branches of a parallel circuit is inversely proportional to the ratio of resistance of each branch.
Consider t resistors with same Ohmic values. If they are in series total resistance Rt = R1 + R2. if they are in parallel then total resistance Rt = 1/R1 + 1/R2. Series connection will have higher resistance.
Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
If the parallel resistors are equal, then the total resistance (in this case, with three resistors) will decrease by a factor of 3. I suggest you verify this with the standard formula for parallel resistance: 1/R = 1/R1 + 1/R2 + 1/R3, replacing the value 30 for R1, R2, and R3, and calculating R, the combined resistance.
The total resistance of resistors in series is simply the sum of the resistance values of those resistors. If the resistors are identical, then you can multiply the resistance of one of them by the number of resistors in the circuit.
What do you mean by a 'parallel delta' circuit -is there such a connection.
What do you mean? In a parallel circuit, the combined (or effective) resistance is less than any individual resistance.
A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.
To find equivalent resistance when you have both parallel and series resistors, start simple and expand... Find the smallest part of the circuit, such as a pair of resistors in series or a pair of resistors in parallel, and compute the equivalent single resistor value. Repeat that process, effectively covering more and more of the circuit, until you arrive at a single resistance that is equivalent to the circuit. For resistors in series: RTOTAL = R1 + R2 For resistors in parallel: RTOTAL = R1R2/(R1+R2)
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
Two resistors in parallel are equivalent to a single component with a lower resistance than either of the pair. Two resistors in series are equivalent to a single component with a resistance equal to the sum of the pair, therefore a higher resistance. For a given potential difference, more current in total will flow through two resistors in parallel than through the same resistors in series.
A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.
The equivalent resistance is the overall effect all of the resistances in a circuit has. Put another way, it is the value a single resistor in a circuit would have to be in order to have the same effect as all of the resistors resistors combined in a given circuit.
You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.