Percent by (basic) mass is easy...
K2 = 39 x 2 = 78
Cr2 = 52 x 2 = 104
O7 = 16 x 7 = 112
% by mass = 112/(78+104+112) = 56/142 = 29.9465%
If you're looking for a more complex/precise derivative that includes the probabalistic mass of the electrons, etc. then it becomes much more complicated.
-D
EBITDA Margin = EBITDA/Sales
You could divide that number by your total income and that should determine the percent.
multiply the money by the percent and divide the sum by the amount of people working on the deal
1,773.60
$131.66
The percentage of potassium is 26,53 %.
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
Potassium dichromate contain potassium, chromium and oxygen.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
such a compound is an oxidizing agent as , KMnO4 , K2Cr2O7 , K2CrO4 ,MnO2 , H2O2 etc.
potassium dichromate
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)
1N of k2cr2o7=49.09 gm/1 L 0.25N=12.2725 gm of k2cr2o7 in 1 L of water.
The chemical formula of potassium dichromate is K2Cr2O7
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
Weigh 4.9035g K2Cr2O7 make up to 1 liter
No, It's totally different. 1M of K2Cr2O7 is 294.19g/water 1L on the other hands, 1N of K2Cr2O7 is 49.04 g/ water 1L