Percent by (basic) mass is easy...
K2 = 39 x 2 = 78
Cr2 = 52 x 2 = 104
O7 = 16 x 7 = 112
% by mass = 112/(78+104+112) = 56/142 = 29.9465%
If you're looking for a more complex/precise derivative that includes the probabalistic mass of the electrons, etc. then it becomes much more complicated.
-D
EBITDA Margin = EBITDA/Sales
You could divide that number by your total income and that should determine the percent.
multiply the money by the percent and divide the sum by the amount of people working on the deal
1,773.60
32
The molecular formula for potassium dichromate is K2Cr2O7. The percentage of oxygen in potassium dichromate is calculated as follows: Molecular weight of oxygen: 16 g/mol Molecular weight of K2Cr2O7: 294 g/mol Percentage of oxygen in K2Cr2O7: (16 g/mol / 294 g/mol) * 100% = 5.44% Therefore, oxygen constitutes approximately 5.44% of the compound potassium dichromate.
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
Potassium dichromate contain potassium, chromium and oxygen.
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
The chemical formula for sodium oxide is Na2O. To determine the mass percent of oxygen in Na2O, we need to calculate the molar mass of oxygen (O) and sodium oxide (Na2O), then use these values to calculate the mass percent of oxygen in Na2O.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
When potassium dichromate (K2Cr2O7) is heated, it decomposes into potassium chromate (K2CrO4) and oxygen gas (O2) is released. The color of the compound changes from orange to yellow as it loses oxygen atoms during the decomposition process.
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
The formula means, among other things, that there are 7 atoms of oxygen in each mole of the compound. Therefore, in 4.00 moles of the compound, there are 28.00 moles of oxygen atoms. Elemental oxygen usually is diatomic, so that there would be the equivalent of 14 moles of diatomic elemental oxygen.
The percent by mass of oxygen in N2O4 is 69,56 %.