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To make NaN₃ (sodium azide), sodium metal is reacted with azide ions, typically derived from ammonium azide. This reaction is performed in a controlled environment due to the compound's sensitivity and potential explosiveness. The resulting product is a white crystalline solid that can be purified through recrystallization. Proper safety precautions must be taken, as sodium azide is highly toxic and can be hazardous.
What else can I help you with?
How much does a cosmetolgist make a year?
That's a wrong question. Cosmetologists do not 'make', they 'make-up'.
How much money do you make per hour if you make 50000 a year?
You would make about $26.00 an hour
How much will you make monthly if you make 39000?
about 3250 a month
What happens if you don't make a profit?
you dont make a profit
If you make 23 dollars an hour how much do you make a year?
At 40 hours per week you make $47,840 a year.
What is the empirical formula for sodium azide?
The empirical formula for sodium azide is NaN3.
What is the chemical formula for sodium azide?
NaN3
What is the total number of moles present in a 52.0 gram sample of NaN3 gram formula mass equals 65.0 mole?
To calculate the total number of moles in the 52.0 gram sample of NaN3, divide the given mass by the molar mass of NaN3. First, determine the molar mass of NaN3 by summing the atomic masses of its elements (sodium, nitrogen, and three times the atomic mass of nitrogen). Then, divide the mass of the sample by the molar mass of NaN3 to find the number of moles.
What is the main gas in an air bag that inflated using the NaN3 reaction?
NaN3 decomposed to form nitrogen gas (N2) and sodium. 2NaN3 --> 2Na + 3N2
When deployed automobile airbags rapidly inflate as sodium azide(NaN3) decomposes into its componet elements. 2NaN3(s)2Na(s) 3N2(g). How many grams of NaN3 are required to form 5.00 grams of nitrogen?
To find the grams of sodium azide (NaN3) required to produce 5.00 grams of nitrogen (N2), we first calculate the moles of N2 produced. The molar mass of N2 is approximately 28.02 g/mol, so 5.00 grams of N2 is about 0.1786 moles (5.00 g / 28.02 g/mol). According to the reaction, 2 moles of NaN3 produce 3 moles of N2. Therefore, 0.1786 moles of N2 corresponds to 0.1191 moles of NaN3 (0.1786 moles N2 * 2/3). Finally, using the molar mass of NaN3 (approximately 65.01 g/mol), we find that 0.1191 moles of NaN3 is about 7.75 grams (0.1191 moles * 65.01 g/mol). Thus, approximately 7.75 grams of NaN3 are required.
What gas fills air bags?
Callod sodium acid ( NaN3 )
Is NaN3 covalent or ionic?
NaN3 (sodium azide) is an ionic compound. It is composed of sodium cations (Na+) and azide anions (N3-) which are held together by ionic bonds due to the transfer of electrons from sodium to azide.
What is the name of this compound NaN3?
The compound NaN3 is called sodium azide. It is commonly used as a propellant in airbags and as a reagent in organic synthesis. Sodium azide is highly toxic and should be handled with caution.
How many moles of N2 are produced by the decomposition of 2.88 mol of sodium azide?
Using the balanced chemical equation for the decomposition of sodium azide, 2NaN3 -> 2Na + 3N2, we can see that 2 moles of Na3N produce 3 moles of N2. Therefore, for 2.88 mol of NaN3, we would produce 2.88 mol * (3 mol N2 / 2 mol NaN3) = 4.32 moles of N2.
How many grams of NaN3 are required to from 6.00 g of N2 gas?
9.28 g
How is sodium azide decomposed?
The chemical equation is:2 NaN3 = 2 Na + 3N2
What is the chemical equation when decomposing sodium azide to sodium nitride?
NaN3 (sodium azide) decomposes into Na (sodium) and N2 (nitrogen gas). The chemical equation is: 2 NaN3(s) → 2 Na(s) + 3 N2(g)
