The answer is 1,54 moles.
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
90 grams is about 0.2 (0.198416) pounds.
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To convert 90 kg to grams, you would multiply 90 by 1000 (since there are 1000 grams in one kilogram), resulting in 90,000 grams.
There are 1000 milligrams in a gram. To convert, you divide by 1000. 90/1000 is 0.09 grams.
The answer is 134,645 grams of NaCl.
At standard conditions, 1 mole of hydrogen reacts with 0.5 moles of oxygen to form 1 mole of water. Therefore, to form 5 moles of water, you will need 5 moles of hydrogen and 2.5 moles of oxygen. The molar mass of water is approximately 18 g/mol, so 5 moles of water would weigh 90 grams.
To calculate the number of moles in 5 grams of oxalic acid (C2H2O4), first determine the molar mass of oxalic acid, which is 90.03 g/mol. Then, divide the mass (5 grams) by the molar mass to get the number of moles. In this case, 5 grams is equal to approximately 0.055 moles of oxalic acid.
90 kg = 90 000 gTo convert from kg to g, multiply by 1000.
First of all we convert the mass of leadto moles. Using the equation moles = mass(g) / Ar (Realtive atomic Mass)_. Mass( g) = 45 g Ar =~ 207 (Periodic Table). Hence moles(Pb) = 45 x 207 Moles (Pb) = 9315 moles. Next using the Avogadro number. 1 moles(of A SUBSTANCE) contains 6.022 x 10^(23) atoms. Hence number of atoms in 9315 moles = 9315 x 6.022 x 10^(23) = 5.61 x 10^(27) atoms. As a 'silly' number. 5,610,000,000,000,000,000,000,000,000 atoms.
To find the number of moles in 9.8 grams of Calcium, you first need to calculate the molar mass of Calcium, which is about 40.08 g/mol. Then, divide the given mass by the molar mass: ( \frac{9.8 , \text{g}}{40.08 , \text{g/mol}} \approx 0.245 , \text{moles})
there are zero 1lb in 90 grams.